Question

我想使用googlesheetv4 api在googlesheet中使用rowno删除一行。任何人都可以为我提供示例代码吗？我创建了一个删除行的方法：

public void deleteRow() {

    BatchUpdateSpreadsheetRequest content = new BatchUpdateSpreadsheetRequest();
    Request request = new Request();
    request.setDeleteDimension(new DeleteDimensionRequest().setRange(new DimensionRange().setDimension("D30:D31")));

    List<Request> requests = new ArrayList<Request>();
    requests.add(request);
    content.setRequests(requests);
    System.out.println(content.getRequests());

    try {
        service.spreadsheets().batchUpdate(IConstant.SPREADSHEET_ID, content);

    } catch (IOException e) {
        e.printStackTrace();
    }
}

Answer 1

正如Migrate to the Google Sheets API中提到的那样，使用Google表格API V4向delete a row提及，使用spreadsheet.batchUpdate请求通过DeleteDimension方法调用进行处理。此请求也可用于删除列，开发人员可以选择仅删除行或列的一部分。

示例代码，用于删除具有给定ID的工作表的第6行：

POST https://sheets.googleapis.com/v4/spreadsheets/spreadsheetId:batchUpdate

{
  "requests": [
    {
      "deleteDimension": {
        "range": {
          "sheetId": sheetId,
          "dimension": "ROWS",
          "startIndex": 5,
          "endIndex": 6
        }
      }
    }
  ],
}

row and column operations中的更多信息可能有所帮助。

Answer 2

您的代码看起来很近，但您没有正确设置DimensionRange。请尝试以下方法：

Request request = new Request()
  .setDeleteDimension(new DeleteDimensionRequest()
    .setRange(new DimensionRange()
      .setSheetId(0)
      .setDimension("ROWS")
      .setStartIndex(30)
      .setEndIndex(32)
    )
  );

Answer 3

您的代码正确，但是您必须确保执行请求。我的代码基本上将您的两个结果结合在一起。

    BatchUpdateSpreadsheetRequest content = new BatchUpdateSpreadsheetRequest();
    Request request = new Request()
        .setDeleteDimension(new DeleteDimensionRequest()
          .setRange(new DimensionRange()
            .setSheetId(Integer.parseInt(Defines.GRID_ID))
            .setDimension("ROWS")
            .setStartIndex(30)
            .setEndIndex(30 + numofrows)
          )
        );

    // request.setDeleteDimension(new DeleteDimensionRequest().setRange(new DimensionRange().setDimension("D30:D31")));

    List<Request> requests = new ArrayList<Request>();
    requests.add(request);
    content.setRequests(requests);

    try {
        sheetsService.spreadsheets().batchUpdate(Defines.GOOGLE_SPREADSHEET_ID, content).execute();

    } catch (IOException e) {
        e.printStackTrace();
    }

Answer 4

我不确定我的方法是否是最好的方法，但它达到了目的，所以我会解释我做了什么。

在要保存的工作表中多保留一列（比如 ROWNUM）数据。
每次在此列中写入相同的字符串“=ROW()” 您正在发布数据，它将为该行生成行 ID

那就用下面的方法吧，希望能帮到你！

public void deleteRows (String range, String textToBeDeleted) {//textToBeDeleted is cell value which will be find in the column and that row will be deleted

try {
    Sheets sheetsService = createSheetsService();
    ValueRange response = sheetsService.spreadsheets().values()
            .get(spreadsheetId, range)
            .execute(); //Getting all the data of the sheet

    List<Request> requests = new ArrayList<>();
    List<List<Object>> allData = response.getValues();
    List<Integer> rowsToBeDeleted = new ArrayList<>();

    for (List<Object> row : allData) {
        if (row.get(0).toString().equalsIgnoreCase(textToBeDeleted)) { //0 is the column value based on which I'll be deleting the row
            rowsToBeDeleted.add(Integer.parseInt(row.get(23).toString())); //23 is the RowNumber column in my case
        }
    }

    BatchUpdateSpreadsheetRequest requestBody = new BatchUpdateSpreadsheetRequest();
    for (int i = rowsToBeDeleted.size() - 1; i >= 0; i--) { //Reverse loop while deleting so that wrong index doesn't get deleted
        Request request = new Request();
        request.setDeleteDimension(new DeleteDimensionRequest()
                .setRange(new DimensionRange()
                        .setSheetId(sheetid)
                        .setDimension("ROWS")
                        .setStartIndex(rowsToBeDeleted.get(i) - 1)
                        .setEndIndex(rowsToBeDeleted.get(i))
                )
        );
        requests.add(request);
    }
    requestBody.setRequests(requests);

    Sheets.Spreadsheets.BatchUpdate deleteRequest =
            sheetsService.spreadsheets().batchUpdate(spreadsheetId, requestBody);

    BatchUpdateSpreadsheetResponse deleteResponse = deleteRequest.execute();

    System.out.println(deleteResponse);

} catch (Exception e) {
    System.out.println(e.getStackTrace());
}}

我想使用googlesheet api v4删除googlesheet中的行

4 个答案: