我正在尝试将图像上传到服务器上的文件夹,并同时在同一个表单中的数据库中存储另一个数据。但它显示错误您没有选择要上传的文件。
以下是我的观点和控制器:
查看:
<form role="form" method="post" action="job_insert" enctype="multipart/form-data">
<div class="box-body">
<div class="form-group">
<label>Job Name*</label>
<input type="text" class="form-control" name="jname" placeholder="Enter Job Name" required>
</div>
<div class="form-group">
<label>Description</label>
<textarea rows="4" cols="10" class="form-control" name="description" required></textarea>
</div>
<div class="form-group">
<label>File input</label>
<input type="file" name="userimage">
</div>
<div class="form-group">
<label>Paper Size*</label>
<div class="form-group">
<label>Paper Cutting Size</label>
<div>
<input id="cutting_size" name="cutting_size" type="text" placeholder="Cutting Size" class="form-control input-md" required>
</div>
</div>
<div class="form-group">
<label>Sheet</label>
<div>
<input id="sheet" name="sheet" type="text" placeholder="No. of Sheet" class="form-control input-md" required>
</div>
</div>
<div class="form-group">
<label>Tin No.</label>
<div>
<input id="sheet" name="tin" type="text" placeholder="Tin No." class="form-control input-md" required>
</div>
</div>
</div>
<!-- /.box-body -->
<div style="margin-left: 600px" class="box-footer">
<button type="submit" class="btn btn-primary">Submit</button>
</div>
</form>
控制器:
public function job_insert()
{
$this->form_validation->set_rules('jname', 'job_name', 'trim');
if($this->form_validation->run()== FALSE)
{
$this->load->view('invalid_jobname');
}
else
{
$this->do_upload();
$data = $_SESSION['email'];
$id = $this->user_model->get_client_id($data);
$data = array('cid' => $id,
'job_name' => $this->input->post("jname"),
'job_id' => $this->input->post("job_id"),
'description' => $this->input->post("description"),
'img_name' => $img_name,
'adate' => Date('Y-m-d'),
'status' => 'NEW',
'paper_size' => $this->input->post("paper_size"),
'paper_type' => $this->input->post("paper_type"),
'cutting_size'=> $this->input->post("cutting_size"),
'sheet'=> $this->input->post("sheet"),
'tin' => $this->input->post("tin"),
'lamination' => $this->input->post("checkboxes"),
'print_type' => $this->input->post("checkboxes1"),
'binding' => $this->input->post("checkboxes2"),
);
$query = $this->user_model->job_insert($data);
if ($query == TRUE)
{
$this->load->view('job_submitted');
}
else
{
$this->load->view('error_page');
}
}
}
这是我的do_upload函数:
public function do_upload()
{
$config = array(
'upload_path' => "./uploads/",
'allowed_types' => "gif|jpg|png|jpeg|pdf",
'overwrite' => FALSE,
'max_size' => "2048000", // Can be set to particular file size , here it is 2 MB(2048 Kb)
'max_height' => "768",
'max_width' => "1024"
);
$this->load->library('upload', $config);
$image = $this->input->post("image");
echo $image;
if(!$this->upload->do_upload('userimage'))
{
$error = $this->upload->display_errors();
echo $error;
}
}
答案 0 :(得分:1)
将此更改为
<input type="file" name="image">
到
<input type="file" name="userfile"/>
和do_upload
if(!$this->upload->do_upload())
要 if(!$ this-&gt; upload-&gt; do_upload(&#39; userfile&#39;))
答案 1 :(得分:0)
在表单标记中提供 enctype =“multipart / form-data”。没有它你就无法上传图片。
答案 2 :(得分:0)
使用以下代码更新表单标记
<form role="form" method="post" action="job_insert" enctype="multipart/form-data">