我有来自Php数据库的图像,格式为
<img src="data:image/jpeg;base64,{{base64_encode($file)}}"/>
//I am able to see the image in this tag
现在使用onclick函数编辑附加的信息,用户也可以更改图像,但为此我需要阅读此图像,点击后应将其粘贴到具有此ID的图像标记中
<img style="max-width:400px;" src="" id="imgretprd">
我研究了一下,开始了解这段代码
var reader = new FileReader();
reader.addEventListener("load", function () {
preview.src = reader.result;
}, false);
if (file) {
reader.readAsDataURL(file);
}
但我不确定如何使用它。
答案 0 :(得分:0)
<!doctype html>
<html>
<head>
<meta content="text/html; charset=UTF-8" http-equiv="Content-Type" />
<title>Image preview example</title>
<script type="text/javascript">
oFReader = new FileReader(), rFilter = /^(?:image\/bmp|image\/cis\-cod|image\/gif|image\/ief|image\/jpeg|image\/jpeg|image\/jpeg|image\/pipeg|image\/png|image\/svg\+xml|image\/tiff|image\/x\-cmu\-raster|image\/x\-cmx|image\/x\-icon|image\/x\-portable\-anymap|image\/x\-portable\-bitmap|image\/x\-portable\-graymap|image\/x\-portable\-pixmap|image\/x\-rgb|image\/x\-xbitmap|image\/x\-xpixmap|image\/x\-xwindowdump)$/i;
oFReader.onload = function (oFREvent) {
document.getElementById("uploadPreview").src = oFREvent.target.result;
};
function loadImageFile() {
if (document.getElementById("uploadImage").files.length === 0) { return; }
var oFile = document.getElementById("uploadImage").files[0];
if (!rFilter.test(oFile.type)) { alert("You must select a valid image file!"); return; }
oFReader.readAsDataURL(oFile);
}
</script>
</head>
<body onload="loadImageFile();">
<form name="uploadForm">
<table>
<tbody>
<tr>
<td><img id="uploadPreview" style="width: 100px; height: 100px;" src="data:image/svg+xml,%3C%3Fxml%20version%3D%221.0%22%3F%3E%0A%3Csvg%20width%3D%22153%22%20height%3D%22153%22%20xmlns%3D%22http%3A//www.w3.org/2000/svg%22%3E%0A%20%3Cg%3E%0A%20%20%3Ctitle%3ENo%20image%3C/title%3E%0A%20%20%3Crect%20id%3D%22externRect%22%20height%3D%22150%22%20width%3D%22150%22%20y%3D%221.5%22%20x%3D%221.500024%22%20stroke-width%3D%223%22%20stroke%3D%22%23666666%22%20fill%3D%22%23e1e1e1%22/%3E%0A%20%20%3Ctext%20transform%3D%22matrix%286.66667%2C%200%2C%200%2C%206.66667%2C%20-960.5%2C%20-1099.33%29%22%20xml%3Aspace%3D%22preserve%22%20text-anchor%3D%22middle%22%20font-family%3D%22Fantasy%22%20font-size%3D%2214%22%20id%3D%22questionMark%22%20y%3D%22181.249569%22%20x%3D%22155.549819%22%20stroke-width%3D%220%22%20stroke%3D%22%23666666%22%20fill%3D%22%23000000%22%3E%3F%3C/text%3E%0A%20%3C/g%3E%0A%3C/svg%3E" alt="Image preview" /></td>
<td><input id="uploadImage" type="file" name="myPhoto" onchange="loadImageFile();" /></td>
</tr>
</tbody>
</table>
<p><input type="submit" value="Send" /></p>
</form>
</body>
</html>
这是来自MDN的演示,但我无法找到源网站。
也许这可以帮到你。
答案 1 :(得分:0)
您可以使用Javascript(如
)设置图像属性 datetime temp humid id
2016-04-03 00:00:00 59.35 43.95 RSOSW_16
2016-04-03 00:15:00 59.45 42.25 RSOSW_16
2016-04-03 00:30:00 58.4 44.35 RSOSW_16
使用Jquery
var imageFile='Base64 String'
document.getElementsByTagName("img")[0].setAttribute("src",imageFile);
答案 2 :(得分:0)
根本不需要FileReader。复制图像源非常简单,只需将src属性从一个转换为另一个:
List<T>
或jQuery:
// for each clickable image, add a 'click' event listener
document.getElementById('clickable-image-id').addEventListener('click',function() {
// set the target source to this image source
document.getElementById('imgretprd').src = this.src;
});