Question

我们说我有2个结果集（2个查询）。

FIELDNAME   VALUE
field1      20.00
field2      13.00
field3      4.00

FIELDNAME   VALUE
field1      20.00
field2      14.00
field3      6.00

我知道query1 EXCEPT query2应该给出

FIELDNAME   VALUE
field2      13.00
field3      4.00

但我真正想要的是从查询的两个方面展示存在差异的任何情况：

FIELDNAME   VALUE
field2      13.00
field3      4.00
field2      14.00
field3      6.00

这可能吗？我想我可以在一个临时表中做一个SELECT UNION。然后删除任何NOT EXISTS字段名不同的行。还有什么更简单的吗？

似乎我可以将INTERSECT，UNION和EXCEPT结合起来并以此结束，但没有太多的运气概念化。

Answer 1

我认为您应该能够使用EXCEPT两次并在结果上使用UNION ALL来获得所需内容：

-- records from the table1 that are not in table2
(SELECT * FROM table1 
EXCEPT 
SELECT * FROM table2)

UNION ALL

-- records from the table2 that are not in table1
(SELECT * FROM table2 
EXCEPT 
SELECT * FROM table1)

其他方法是使用UNION获取所有表的组合，然后使用EXCEPT消除所有相交记录：

-- Union of both tables
(SELECT * FROM table1 
UNION ALL
SELECT * FROM table2)

EXCEPT   -- Exclude the records ...

-- ... that are in both tables
(SELECT * FROM table1 
INTERSECT 
SELECT * FROM table2)

Answer 2

就像XOR操作：

DECLARE @Table1 TABLE(Name nvarchar(20), Value decimal)
DECLARE @Table2 TABLE(Name nvarchar(20), Value decimal)

INSERT INTO @Table1 
VALUES
(N'field1', 20.00),
(N'field2', 13.00),
(N'field3',  4.00)


INSERT INTO @Table2 
VALUES
(N'field1', 20.00),
(N'field2', 14.00),
(N'field3',  6.00)


SELECT *
FROM
(
    SELECT *
    FROM @Table1 AS t
    EXCEPT (SELECT * FROM @Table2 AS t)
) AS a
UNION
SELECT *
FROM 
(
    SELECT *
    FROM @Table2 AS t
    EXCEPT (SELECT * FROM @Table1 AS t)
) AS b

Answer 3

根据您的帖子，您已尝试使用INTERSECT，UNION和EXCEPT组合，但未获得输出。

尝试使用（INTERSECT，UNION和EXCEPT）来获取它。

DECLARE @Table1 TABLE(Name nvarchar(20), Value decimal(18,2))
DECLARE @Table2 TABLE(Name nvarchar(20), Value decimal(18,2))

INSERT INTO @Table1 
VALUES
(N'field1', 20.00),
(N'field2', 13.00),
(N'field3',  4.00)


INSERT INTO @Table2 
VALUES
(N'field1', 20.00),
(N'field2', 14.00),
(N'field3',  6.00)

select *From @Table1
union
select *From @Table2
except
select *From @Table1
intersect
select *From @Table2

使用EXCEPT或INTERSECT仅显示不匹配的行

3 个答案: