Question

public function store(Request $request)
{
   $this->validate($request, array(
       'title' => 'required|max:255|min:2',
       'slug' => 'required|alpha_dash|unique:articles,slug',
       'category_id' => 'required|integer',
       'content' => 'required|min:2'
   ));

   $article = new Article;
   $article->title = $request->title;
   $article->slug = $request->slug;
   $article->category_id = $request->category_id;

   $article->content = $request->content;
   $article->save();

   Session::flash('success', 'Your article has been published.');
   return redirect()->route('article.show', $article->id);
}

文章表上有一个user_id列，

这是我的商店功能，但是当我创建帖子时，我正在寻找一种方法将登录的用户ID存储到文章表格中的user_id列。

Answer 1

获取auth ed用户。

$article->user_id = Auth::user()->id;
$article->save();

Answer 2

简单

$article->user_id = Auth::user()->id;

它会将经过身份验证的用户ID存储在文章表的user_id字段中。

在您的情况下，将商店代码更改为

public function store(Request $request)
{
   $this->validate($request, array(
       'title' => 'required|max:255|min:2',
       'slug' => 'required|alpha_dash|unique:articles,slug',
       'category_id' => 'required|integer',
       'content' => 'required|min:2'
   ));

   $article = new Article;
   $article->title = $request->title;
   $article->slug = $request->slug;
   $article->category_id = $request->category_id;
   //it will store the current logged in user id in user_id field
   $article->user_id = Auth::user()->id;

   $article->content = $request->content;
   $article->save();

   Session::flash('success', 'Your article has been published.');
   return redirect()->route('article.show', $article->id);
}

Answer 3

但是还有另一种方法，甚至不使用名称空间和全部。

您可以使用以下代码解决此问题：

$article->user_id =  auth()->user()->id;

代替：

$article->user_id = Auth::user()->id;

Laravel试图将用户ID存储到posts表中

3 个答案: