var products = [{
"name": "Lusicious Jello Mix",
"description": ["Very Elegant", "Trending item", "Come in Purple"],
"price": 80.65
}, {
"name": "Tarnished Standing Desk",
"description": ["Modular", "Works for both Tall and Loud People", "Smells like Productivity"],
"price": 1654.99
}, {
"name": "Hand-made Hand Grenades",
"description": ["Such gift!", "Much boom!", "Very safe for kids"],
"price": 10.44
}, {
"name": "Pan-fried Cookie Dough",
"description": ["Chocolate", "Family-size", "Hot Mess"],
"price": 16.99
}, {
"name": "Fancy Dress Hanger",
"description": ["Keep organized", "On Sale"],
"price": 67.32
}, {
"name": "Snarky Britsh Mustache 3-Pack",
"description": ["Sharing is caring!", "Hugs not drugs", "As seen on 'So You Think You Can Dance - Nigeria!'"],
"price": 1.99
}, ];
for (var x=0; x<products.length; x++){
//PRODUCT NAME
var prodname = document.createElement("h3");
prodname.innerHTML = products[x].name;
var listname = document.getElementById("name");
listname.appendChild(prodname);
var proddesc = document.createElement("h3");
proddesc.innerHTML = products[x].description;
var listdesc = document.getElementById("description");
listdesc.appendChild(proddesc);
var prodprice = document.createElement("h3");
prodprice.innerHTML = products[x].price;
var listprice = document.getElementById("price");
listprice.appendChild(prodprice);
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Shopping Cart</title>
<script src="js/app.js"></script>
<link rel="stylesheet" href="css/styles.css"></link>
</head>
<body>
<div>
<div id="shopHead"><h3>Shopping Cart<h3/>
<h3 id="name"></h3>
<h3 id="description"></h3>
<h3 id="price"></h3>
</div>
</div>
</body>
</html>
这是我在名为products的数组中的对象。我使用数组然后使用DOM在我的HTML页面中显示。然而它并没有按顺序出现。我想在位置0的数组中显示名称,然后在位置0处显示描述,最后定价在位置0.相反,它显示我的所有名称,然后是所有描述,后跟所有价格。这是一个简单的解决方案,我确定但是我被卡住了。
答案 0 :(得分:0)
试试这个
var displayBox = document.createElement("h3");
displayBox.innerHTML = products[x].name + " "+ products[x].description + " "+products[x].price;
var listname = document.getElementById("name");
listname.appendChild(displayBox);