Laravel Blade Echo

Question

我试图理解laravel。 在我的测试中，我创建了一个这样的控制器：

    public function getDirectorySize( $path = null)
{ 
$path="/folder/"; 
$pathlog="/laravel.log"; 
$pathbackup="/folder/"; 
$ar=getDirectorySize($path); 

$totalsize = 0; 
$totalcount = 0; 
$dircount = 0; 
if ($handle = opendir ($path)) 
{ 
while (false !== ($file = readdir($handle))) 
{ 
  $nextpath = $path . '/' . $file; 
  if ($file != '.' && $file != '..' && !is_link ($nextpath)) 
  { 
    if (is_dir ($nextpath)) 
    { 
      $dircount++; 
      $result = getDirectorySize($nextpath); 
      $totalsize += $result['size']; 
      $totalcount += $result['count']; 
      $dircount += $result['dircount']; 
    } 
    elseif (is_file ($nextpath)) 
    { 
      $totalsize += filesize ($nextpath); 
      $totalcount++; 
    } 
  } 
} 
} 
closedir ($handle); 
$total['size'] = $totalsize; 
$total['count'] = $totalcount; 
$total['dircount'] = $dircount; 
return $total; 

} 

在我的刀片中我想显示如下数据：

        Details for the path : {{ $path }} 
        Details for the log : {{ $pathlog }}
        Details for the backup : {{ $pathbackup }} 
        Total size : {{ sizeFormat($ar['size']) }}
        No. of files : {{ $ar['count'] }} 
        <? echo "No. of directories : ".$ar['dircount']."<br>"; ?>

但我收到了这个错误：

Undefined variable: path

我想显示此功能的任何信息

Answer 1

你能尝试这样的事吗？

public function yourControllerFunction() {
    $path="/folder/"; 
    $pathlog="/laravel.log"; 
    ...
    // Add variables you want to pass to the view
    $data = array(
        'path' => $path,
        'pathlog' => $pathlog,
    )
    return view('view_file', $data);
}

然后在视图中，您应该能够访问$ path和$ pathlog。