我有一个小文本文件,在不同的行上包含几个整数。
我编写了以下程序(只是一个名为ReadFromFile
的函数),以便读取整数并将它们分配给某些变量。
我想知道我是否可以改善它,以及如何?我尝试读取整数,但意识到我会因StreamReader
而出错,所以我继续使用字符串。
无论如何我可以改进这个程序吗?
所有内容都按以下数字读取,将前两个变量分配给两个变量,并将其余变量放在一个列表中。
3
4
8
8
8
8
8
8
所以,我会:var1 = 3
,var2 = 4
,myList = [8,8,8,8,8,8]
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
namespace Practice
{
class Program
{
static void Main(string[] args)
{
// Read the specifications from the file.
ReadFromFile();
// Prevent the console window from closing.
Console.ReadLine();
}
/// The function that reads the input specifications from a file.
public static void ReadFromFile()
{
string localPath = @"C:\Desktop\input.txt";
StreamReader sr = new StreamReader(localPath);
// Read all the lines from the file into a list,
// where each list element is one line.
// Each line in the file.
string line = null;
// All lines of the file.
List<string> lines = new List<string>();
while ( ( line = sr.ReadLine() ) != null )
{
lines.Add(line);
Console.WriteLine(line);
}
// Display the extracted parameters.
Console.WriteLine( lines[0] + " var1");
Console.WriteLine( lines[1] + " var2");
// Put the rest in a separate list.
List<int> myList = new List<int>();
for (int i = 2; i < lines.Count; i++)
{
Console.WriteLine("item {0} = {1}", i-1, lines[i] );
myList.Add( Int32.Parse( lines[i] ) );
}
sr.Close();
}
}
}
答案 0 :(得分:3)
var vals = File.ReadAllLines(path).Select(int.Parse).ToList();
如果您有标题行,则可能需要Skip(...)
;例如,匹配您的for(int i = 2; ...)
:
var vals = File.ReadAllLines(path).Skip(2).Select(int.Parse).ToList();
答案 1 :(得分:3)
您可以按照以下方式编写:
public static void ReadFromFile(string localPath) // paremetrizing the path for more flexibility
{
StreamReader sr = new StreamReader(localPath);
// extrating the lines from the file
List<int> lines = Regex.Split(sr.ReadToEnd(), "\r\n").Select(int.Parse).ToList();
// we can close the reader as we don't need it anymore
sr.Close();
Console.WriteLine( lines[0] + " var1");
Console.WriteLine( lines[1] + " var2");
// removing the first 2 elements
lines = lines.Skip(2).ToList();
for (int i = 0; i < lines.Count; i++)
{
Console.WriteLine("item {0} = {1}", i-1, lines[i] );
}
}