Question

有两个阵列：

First Array：

Array
(
  [0] => ACTIVITIES
  [1] => 50
  [2] => 35
  [3] => THIRTY
  [4] => FIVE
  [5] => PASS
)

第二阵列：

Array 
(
  [0] => EXTRA CURRICULAR ACTIVITIES
  [1] => 50
  [2] => 35
  [3] => THIRTY
  [4] => FIVE
  [5] => PASS
)

期望输出：

private void button1_Click(object sender, EventArgs e)
    {
        DateTime dateTime = DateTime.ParseExact(textBox1.Text, "HH:mm", System.Globalization.CultureInfo.CurrentCulture);
        TimeSpan time = new TimeSpan(8,40,0);
        DateTime outputTime = dateTime.Add(time);
        textBox2.Text = outputTime.ToString("HH:mm");
    }

两个数组应该是动态的，我需要先加到第二个，请帮帮我

Answer 1

您需要implode第一个数组，并将结果添加到第二个数组的第一个值：

$array1 = array('EXTRA', 'CURRICULAR');
$array2 = array('ACTIVITIES', 50, 35, 'THIRTY', 'FIVE', 'PASS');

$string = implode(' ', $array1);
$array2[0] = $string . ' ' . $array2[0];

var_dump($array2);

结果：

array (size=6)
  0 => string 'EXTRA CURRICULAR ACTIVITIES' (length=27)
  1 => int 50
  2 => int 35
  3 => string 'THIRTY' (length=6)
  4 => string 'FIVE' (length=4)
  5 => string 'PASS' (length=4)

如何在php中将数组合并为单个数组

1 个答案: