Question

我想使用spring boot构建一个请求方法：我必须使用restful api并将其转换为另一个rest端点。

我在www.exampleapiurl.com/details上有一个json回复

[{
      "name": "age",
      "value": "Child"
  },
{
      "name": "recommendable",
      "value": true
    },

{
      "name": "supported",
      "value": yes
    },
]
[{
      "name": "age",
      "value": "Adult"
  },
{
      "name": "recommendable",
      "value": true
    },

{
      "name": "supported",
      "value": no
    },
]

我希望回复是：

[{
      "age": "Child"
  },
{
      "recommendable": true
    },

{
      "supported": "yes"
    },
]
[{
      "age": "Adult"
  },
{
      "recommendable": true
    },

{
      "supported": "no"
    },
]

为此，我有一个带getter和setter的属性类： Attributes.class

@JsonIgnoreProperties(ignoreUnknown = true) 
public class Attributes {
private String age;
private boolean recommendable;
private String supported;

getter and setter for these:
}

这是我的service.java类

@Service
public class CService {
    private static RestTemplate restTemplate;
    public String url;

    @Autowired
    public CService(String url) {
        this.url = url;
    }

    public Attributes getAttributes() {

        HttpHeaders headers= new HttpHeaders();
        headers.add("Authorization", "some value");
        HttpEntity<String> request = new HttpEntity<String>(headers);
        ResponseEntity<String> response = restTemplate.exchange(url, HttpMethod.GET, request, Attributes.class);
        return response.getBody();

    }
}

这是我的controller.class

@Controller
public class CController {
    private CService cService;
    @Autowired
    public CController(CService cService) {
        this.cService = cService;
    }

    @RequestMapping(value="/example")
    @ResponseBody
    public Attributes getCAttributes() {
        return cService.getAttributes();    }  

}

授权成功但是，我现在没有得到任何回复

Answer 1

您可以做的是创建一个模型类，以便从示例API中恢复响应如下。

@JsonIgnoreProperties(ignoreUnknown = true)
public class Details{
    private String name;
    private String value;

    @JsonProperty("value")
    public String getValue() {
        return value;
    }
    public void setValue(String value) {
        this.value = value;
    }

    @JsonProperty("name")
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
}

然后按如下所示更改调用RestTemplate代码

     Details[] details = null;
//Keeps the example API's data in array.


      ResponseEntity<Details[]> response = restTemplate.exchange(url, HttpMethod.GET, request, Details[].class);
            details = response.getBody();

//下一步是处理此数组并将响应发送回您的客户端

    List<Attributes> attributes = new ArrayList<Attributes>();
    Attributes attr = null;
    for(Details detail : details) {
        attr = new Attributes();
       //set the values here 
    }

//returns the attributes here 
attributes.toArray(new Attributes[attributes.size()]);

在spring boot中以JSON格式获取数据

1 个答案: