Question

所以我已经成功地在控制器中创建了这些方法，所以当有人登录我的网站并且它是管理员（来自db的列admin中的值为1，普通用户的值为0），将他重定向到只有他能看到的页面。现在，我想显示管理员不是管理员的所有用户，但我不知道如何让它真诚地工作。

型号：

 public function display_users() {

    $query = $this->db->query('SELECT id, fname, email, username, password FROM register WHERE admin = 0');
    return $query->result();
}

也在模型中试过这个：

  $this->db->select('id', 'fname', 'lname', 'email', 'username', 'password')
           ->where('admin', 0)
           ->get('register')
           ->result_array();

控制器：

   public function admin() {

    $isLogged = $this->session->userdata('email');

    if ($isLogged) {
        $check_admin = $this->signup_model->admin();

        if ($check_admin == 1) {
            $this->signup_model->display_users();

            $this->load->view('navbar');
            $this->load->view('header');
            $this->load->view('admin');
            $this->load->view('footer');
        } else {
            redirect('users/login');
        }
    }
}

查看：

<table class="usersTable">
<thead>
    <tr class="column">
        <th class="cell">ID</th>
        <th class="cell">First Name</th>
        <th class="cell">Last Name</th>
        <th class="cell">Email</th>
        <th class="cell">Username</th>
        <th class="cell">Password</th>

    </tr>
</thead>

<tbody>
     <?php
    if ($result->num_rows > 0) { 

        while ($row = $result->fetch_assoc()) {
    ?>
    <tr>
        <td class="cell"><?php echo $row->id; ?> </td>
        <td class="cell"><?php echo $row->fname; ?> </td>
        <td class="cell"><?php echo $row->lname; ?> </td>
        <td class="cell"><?php echo $row->email; ?> </td>
        <td class="cell"><?php echo $row->username; ?> </td>
        <td class="cell"><?php echo $row->password; ?> </td>


    </tr>
    <?php }} ?>
</tbody>

Answer 1

请勿在视图中使用数据库功能。您需要在控制器中设置一个变量并将其发送到您的视图，如下所示：

模型

public function display_users() {

    $query = $this->db->query('SELECT id, fname, email, username, password FROM register WHERE admin = 0');
    return $query->result_array();
}

控制器

public function admin() {
    $return = array();
    $isLogged = $this->session->userdata('email');

    if ($isLogged) {
        $check_admin = $this->signup_model->admin();

        if ($check_admin == 1) {
            $return['users'] = $this->signup_model->display_users();

            $this->load->view('navbar');
            $this->load->view('header');
            $this->load->view('admin', $return);
            $this->load->view('footer');
        } else {
            redirect('users/login');
        }
    }
}

查看：

<table class="usersTable">
<thead>
    <tr class="column">
        <th class="cell">ID</th>
        <th class="cell">First Name</th>
        <th class="cell">Last Name</th>
        <th class="cell">Email</th>
        <th class="cell">Username</th>
        <th class="cell">Password</th>

    </tr>
</thead>

<tbody>
     <?php foreach ($users as $user) { ?>
    <tr>
        <td class="cell"><?php echo $user['id']; ?> </td>
        <td class="cell"><?php echo $user['fname']; ?> </td>
        <td class="cell"><?php echo $user['lname']; ?> </td>
        <td class="cell"><?php echo $user['email']; ?> </td>
        <td class="cell"><?php echo $user['username']; ?> </td>
        <td class="cell"><?php echo $user['password']; ?> </td>
    </tr>
    <?php } ?>
</tbody>

Answer 2

试试这个：

// Get the role id of logged in user in some variable like $roleId

if($roleId == 1)   // Visible only for admin
{
    $resultSet = $this->db->query("SELECT id, fname, email, username, password FROM register WHERE role != '1'");
    // It will give you the user list other than admin role.
    return $resultSet;
}

控制器：

if（$ check_admin == 1）{ $ result = $ this-＆gt; signup_model-＆gt; display_users（）;

        // pass this variable on the view so that you can use it there.

        $this->load->view('navbar');
        $this->load->view('header');
        $this->load->view('admin', $result);   // like that
        $this->load->view('footer');
    } else {
        redirect('users/login');
    }

CodeIgniter显示来自db的不是admin的用户

2 个答案: