Question

我有这样一个数组 -

arr = ["0.5", " 2016-08-25 11:02:00 +0530", " test 1",
       " 0.75", " 2016-08-25 11:02:00 +0530", " test 2"]

我希望它以这样的表格形式显示 -

0.5 11:02 test 1
0.75 11:02 test 2

Answer 1

a = ["0.5", " 2016-08-25 11:02:00 +0530", " test 1", " 0.75", " 2016-08-25 11:02:00 +0530", " test 2"]

a.each_slice(3) do |x, y, z|
  puts "#{x.strip} #{y[/\d\d:\d\d/]} #{z.strip}"
end

Answer 2

另一种方法：

 arr = ["0.5", " 2016-08-25 11:02:00 +0530", " test 1", " 0.75", " 2016-08-25 11:02:00 +0530", " test 2"] 

 arr.each_slice(3).map do |x|
   x[1] = Time.parse(x[1]).strftime("%H:%M"); x.map(&:strip) 
 end.map{ |y| puts y.join(' ') }

0.5 11:02测试1
0.75 11:02测试2

Answer 3

我将arr的元素加入到每个元素之间有空格的字符串中，然后扫描字符串，将结果保存到三个捕获组，这产生了一个包含两个三元素数组的数组。最后，我加入了两个数组中每个数组的三个元素，并使用puts打印结果。

r = /
    (\d+\.\d+)    # match a float in capture group 1
    .+?           # match > 1 of any characters, lazily (?)
    (\d{1,2}:\d2) # match the time in capture group 2
    .+?           # match > 1 of any characters, lazily (?)
    (test\s\d+)   # match 'test' followed by > 1 digits in capture group 3
    /x            # free-spacing regex definition mode

puts arr.join(' ').scan(r).map { |a| a.join(" ") }

打印

0.5 11:02 test 1
0.75 11:02 test 2

这三个步骤如下。

a = arr.join(' ')
  #=> "0.5  2016-08-25 11:02:00 +0530  test 1  0.75  2016-08-25 11:02:00 +0530  test 2"
b = a.scan(r)
  #=> [["0.5", "11:02", "test 1"],
  #    ["0.75", "11:02", "test 2"]] 
c = b.map { |a| a.join(" ") }
  #=> ["0.5 11:02 test 1", "0.75 11:02 test 2"]

然后puts c打印上面显示的结果。

以表格形式显示数组

3 个答案: