Question

我有一个对象如下。

public class person
{

  public int ID { get; set; }
  public string name { get; set;}
}

我有一个将Ienumerable转换为此对象列表的转换器。（通过从那里映射这些ID和名称（它们也只有ID和名称）。怎么办？

Answer 1

如果你有

.ToList()

...对于任何IEnumerable<>：

，您应自动拥有

IEnumerable<person> people = SomeMethod();

List<person> peopleList = people.ToList();

扩展名方法

import datetime as dt

if __name__ == "__main__":
    weekend_index = (6, 5)  # Sunday, Saturday
    requested_range = (dt.datetime(2016, 7, 9, 0, 0), dt.datetime(2016, 8, 11, 0, 0))

    start, end = requested_range
    sun, sat = weekend_index
    cur = start
    my_range = []

    while cur < end:
            cr = []
            cr.append(cur)
            cur = end if end < cur+dt.timedelta(days=6) else (cur+dt.timedelta(days=(sun if cur.weekday() == sun else (sat-cur.weekday()))))
            cr.append(cur)
            cur += dt.timedelta(days=1)
            my_range.append(cr)

print(my_range)  # Returns:
# [[datetime.datetime(2016, 7, 9, 0, 0), datetime.datetime(2016, 7, 9, 0, 0)],
#  [datetime.datetime(2016, 7, 10, 0, 0), datetime.datetime(2016, 7, 16, 0, 0)],
#  [datetime.datetime(2016, 7, 17, 0, 0), datetime.datetime(2016, 7, 23, 0, 0)],
#  [datetime.datetime(2016, 7, 24, 0, 0), datetime.datetime(2016, 7, 30, 0, 0)],
#  [datetime.datetime(2016, 7, 31, 0, 0), datetime.datetime(2016, 8, 6, 0, 0)],
#  [datetime.datetime(2016, 8, 7, 0, 0), datetime.datetime(2016, 8, 11, 0, 0)]]

如何将转换器映射属性中的ienumerable转换为列表

1 个答案: