Question

当我点击django上的链接时，我收到错误404，我花了很多时间试图看看我做错了什么但没有运气。

这是我的index.html

<!DOCTYPE html>
<html>
<head>
<title>Page Title</title>
</head>
<body>

<h1>{{title}}</h1>

{% for obj in object_list %}
{% url "detail" id=obj.id %}
<a href = '{{obj.get_absolute_url}}'> {{obj.title}}</a><br/>
{{obj.content}} <br/>
{{obj.timestamp}} <br/>
{{obj.updated}} <br/>
{{obj.id}} <br/>


{% endfor %}    
</body>
</html>

这是我的urls.py

from django.conf.urls import url
from django.contrib import admin

from .views import (
    post_list,
    post_create,
    post_detail,
    post_update,
    post_delete,
    )

urlpatterns = [
    url(r'^$', post_list),
    url(r'^create/$', post_create),
    url(r'^detail/(?P<id>\d+)/$', post_detail, name='detail'),
    url(r'^update/$', post_update),
    url(r'^delete/$', post_delete),

]

这是我的views.py

from django.http import HttpResponse
from django.shortcuts import render, get_object_or_404

from .models import Post

# Create your views here.

def post_create(request):
    return HttpResponse("<h1>Create</h1>")

def post_detail(request, id): # retreive
    instance = get_object_or_404(Post, id=id)
    context = {
        "title": instance.title,
        "instance": instance,
    }
    return render(request, "post_detail.html", context) 

def post_list(request): # list of posts
    queryset = Post.objects.all
    context = {
        "title": "List",
        "object_list": queryset,
    }
    return render(request, "index.html", context) 

def post_update(request):
    return HttpResponse("<h1>Update</h1>")  

def post_delete(request):
    return HttpResponse("<h1>Delete</h1>")

这是我的models.py

from __future__ import unicode_literals

from django.db import models

# Create your models here.
class Post(models.Model):
    title = models.CharField(max_length = 120)
    content = models.TextField()
    updated = models.DateTimeField(auto_now=True, auto_now_add = False )
    timestamp = models.DateTimeField(auto_now=False, auto_now_add = True )

    def __unicode__(self):
        return self.title


    def __str__(self):
        return self.title

    def get_absolute_url(self):
        return "/posts/%s" %(self.id)

Answer 1

您的get_absolute_url方法会返回/posts/<id>格式的网址，但您的网址预计会/posts/detail/<id>。

您应该使用reverse功能，而不是对方法中的URL进行硬编码：

from django.urls import reverse
...
def get_absolute_url(self):
    return reverse('detail', kwargs={'id': self.id})

django urls的错误

1 个答案: