实施例

Question

有没有办法从java中的字符串中拆分单词？

String my ="StackOverFlow PF Apple FT Laptop HW."

PF =平台，FT =水果，HW =硬件。

预期输出应为

StackOverFlow  is a Platform.
Apple  is a Fruit.
Laptop is a hardware.

我这样做：

String[] words = my.split(" ");
  for(int u=0 ; u<words.length ; u++){
      System.out.println( words(u));
  }

Answer 1

如果您可以保证值将按上述顺序排列，那么这样的事情应该起作用

public static void main(String[] args) {
    String my = "StackOverflow PF Apple FT Laptop HW";
    String[] words = my.split(" ");
    for (i = 0; i < words.length; i++) {
        if (i % 2 == 0) {
            System.out.print(words(i) + " is a ");
        } else {
            System.out.println(getTranslation(words(i)));
        }
    }
}

private String getTranslation(String code) {
    if ("PF".equals(code)) {
        return "Platform";
    }
    //etc...
}

基本上，这将做的是将字符串拆分为所有单词。由于单词是“配对”在一起，它们将以2个为一组。这意味着您可以检查单词的索引是偶数还是奇数。如果它是偶数，那么你知道它是第一个配对词，这意味着你可以将“is a”字符串附加到它上面。如果它是奇数，那么你想附加翻译的值。

Answer 2

使用正则表达式amd将孔文本分成2个单词组...

然后用空格分割数组的每个元素，你就完成了！

实施例

public static void main(String[] args) throws ParseException {
String inputTxt = "StackOverFlow PF Apple FT Laptop HW.";
String[] elements = inputTxt.split("(?<!\\G\\w+)\\s");
System.out.println(Arrays.toString(elements));
System.out.println(elements[0].split(" ")[0] + " is a Platform");
System.out.println(elements[1].split(" ")[0] + " is a Fruit");
System.out.println(elements[2].split(" ")[0] + " is a Hardware");
}

Answer 3

鉴于您的问题规格有限，没有理由分开。您可以像这样替换占位符：

String my = "StackOverFlow PF Apple FT Laptop HW.";
my = my.replaceAll("PF[\\s.]?", "  is a Platform.\n");
my = my.replaceAll("FT[\\s.]?", "  is a Fruit.\n");
my = my.replaceAll("HW[\\s.]?", " is a hardware.\n");
System.out.print(my);

输出：

StackOverFlow   is a Platform.
Apple   is a Fruit.
Laptop  is a hardware.

Answer 4

public class StackOverflow {

    public static void main(String[] args) {
        // Fields
        String myString = "StackOverFlow PF Apple FT Laptop HW";

        String[] tokens = myString.split(" ");

        for (int i = 0; i < tokens.length; i++) {
            System.out.print(tokens[i]);
            // Every other token
            if (i % 2 == 0) {
                System.out.print(" is a " + convert(tokens[i + 1]));
                i++;
            }
            System.out.println();
        }

    }

    /**
     * convert method turns the abbreviations into long form
     */
    private static String convert(String s) {
        String str;
        switch (s) {
            case "PF":
                str = "Platform";
                break;
            case "FT":
                str = "Fruit";
                break;
            case "HW":
                str = "Hardware";
                break;
            default:
                str = "Unknown";
                break;
        }
        return str;
    }

}

将特定单词与java中的字符串分开

4 个答案:

实施例