Question

使用Embed标签，我们不仅可以在swf文件中嵌入swf或jpg等，还可以嵌入不支持的文件格式，如：

Embed[(source="mzip.zip", mimeType="application/octet-stream")]

public static MyZip:Class;

当我实例化这样一个类时，我会得到什么类型的对象？是否可以从这个类中获取ByteArray？

当我这样做时： package { import flash.utils.ByteArray;



public final class Resource {       
    [Embed(source="p2.zip", mimeType="application/octet-stream")]
    public static const MyZip:Class;

    public static function getByteArrayFromZip():ByteArray {
        var zip:ByteArray = new MyZip as ByteArray;
        return zip;
    }
}

public final class Resource { [Embed(source="p2.zip", mimeType="application/octet-stream")] public static const MyZip:Class; public static function getByteArrayFromZip():ByteArray { var zip:ByteArray = new MyZip as ByteArray; return zip; } }

和

}

  public class Main extends Sprite {

        private var ship:Bitmap;
        private var lib:FZipLibrary;

    public function Main() {            
        lib = new FZipLibrary();    
        lib.formatAsBitmapData(".jpg");       
        lib.addEventListener(Event.COMPLETE,onCompleteHandler);

        var fzip:FZip = new FZip();
        fzip.loadBytes(Resource.getByteArrayFromZip());
        lib.addZip(fzip);
    }

   private function onCompleteHandler(evt:Event) {
        var image:BitmapData = lib.getBitmapData("assets/graphics/scratchers/myimg.jpg");
        trace("Size: " + image.width + "x" + image.height); 
        var sa0img0:Bitmap = new Bitmap(image);
        addChild(sa0img0);
   }
}

我收到以下错误： public function Main() { lib = new FZipLibrary(); lib.formatAsBitmapData(".jpg"); lib.addEventListener(Event.COMPLETE,onCompleteHandler); var fzip:FZip = new FZip(); fzip.loadBytes(Resource.getByteArrayFromZip()); lib.addZip(fzip); } private function onCompleteHandler(evt:Event) { var image:BitmapData = lib.getBitmapData("assets/graphics/scratchers/myimg.jpg"); trace("Size: " + image.width + "x" + image.height); var sa0img0:Bitmap = new Bitmap(image); addChild(sa0img0); } }

Answer 1

是的，只需实例化MyZip并转换为ByteArray。

Embed[(source="mzip.zip", mimeType="application/octet-stream")]
public static var MyZip:Class;

var zip:ByteArray = new MyZip() as ByteArray;

嵌入未知的文件格式

1 个答案: