NotifyIcon单击事件未触发

时间:2016-08-24 18:34:45

标签: c# windows console-application

class MainProgram
{
    static NotifyIcon _notifyIcon;

    public static void Main()
    {
        _notifyIcon = new NotifyIcon();
        _notifyIcon.Icon = new Icon("icon.ico");
        _notifyIcon.Click += NotifyIconInteracted;
        _notifyIcon.Visible = true;

        while(true)
        {
            Thread.Sleep(1000);
        }
    }

    static void NotifyIconInteracted(object sender, EventArgs e)
    {
        throw new NotImplementedException();
    }
}

以上是最低限度的例子。由于某种原因,永远不会调用NotifyIconInteracted方法。显示通知图标,我多次左/右点击它,事件就不会被激活。

2 个答案:

答案 0 :(得分:2)

如果您只是定期检查,为什么不使用计时器而不是while循环?使用计时器不会像while()循环一样锁定程序。

using System;
using System.Timers;
using System.Windows.Forms;

namespace SONotify
{
    class Program
    {
        private static System.Timers.Timer _timer;
        private static NotifyIcon _notify;

        static void Main(string[] args)
        {
            Console.WriteLine("Press enter to exit");
            SetIcon();
            SetTimer();

            Application.Run();

            Console.ReadLine();

            _timer.Stop();
            _timer.Dispose();
        }

        private static void SetIcon()
        {
            _notify = new NotifyIcon();
            _notify.Icon = new System.Drawing.Icon("icon.ico");
            _notify.Click += NotifyIconInteracted;
            _notify.Visible = true;
        }

        private static void SetTimer()
        {
            _timer = new System.Timers.Timer(2000); //Timer goes off every 2 seconds
            _timer.Elapsed += Timer_Elapsed;
            _timer.AutoReset = true;
            _timer.Enabled = true;
        }

        private static void Timer_Elapsed(object sender, ElapsedEventArgs e)
        {
            Console.WriteLine("Timer fired");
        }

        private static void NotifyIconInteracted(object sender, EventArgs e)
        {
            Console.WriteLine("Icon clicked");
        }
    }
}

答案 1 :(得分:0)

while(true)锁定主线程。

尝试用

替换while(true)块
Application.Run();