Question

如何编写如下查询：

SELECT userid, 
 (IF field IN(1,2,3,900,658,4,5,6,9,10,11,12,13,10025,14,15,16,17,18,19) score = score +20, ELSE IF field IN(23,45,67,777,53,54) score = score + 40,
  ELSE IF field IN(120,332,563,334,634,423,333) score = score + 60) AS score 
 WHERE field IN(1,2,3,900,658,4,5,6,9,10,11,12,13,10025,14,15,16,17,18,19,23,45,67,777,53,54,120,332,563,334,634,423,333) 
GROUP BY userid ORDER BY score DESC

我试图找到将字段设置为给定数字之一的所有用户。某些数字有不同的分数（20分，40分和60分），所以我需要将分数相加得到每个用户ID的总分，然后按总分对用户进行排名。

Answer 1

您可能正在寻找：

SELECT   userid, 
         sum(
             CASE
                WHEN field IN (1,2,3,4,5,6,9,10,11,12,13,14,15,16,17,18,19) THEN 20 
                WHEN field IN (23,45,67,53,54) THEN 40
                ELSE 60 
             END) AS score
FROM     mytable 
WHERE    field IN (1,2,3,4,5,6,9,10,11,12,13,14,15,16,17,18,19,23,45,67,53,54,120,
                   332,563,334,634,423,333)
GROUP BY userid
ORDER BY score DESC

Answer 2

你错过了桌子，你可以用案例

select UserId,
     case 
       when field < 20 then  Score + 20
       when field IN(23,45,67,53,54) then  Score + 40
       else  score + 60
      end as Score
FROM mytable
where field IN(1,2,3,4,5,6,9,10,11,12,13,14,15,16,17,18,19,23,45,67,53,54,120,332,563,334,634,423,333) 
group by UserId
order by Score desc

MySQL：如果选择内的IN（）语句？我该如何查询？

2 个答案: