我有一个数字列表(50,000+),我需要在每个唯一组的末尾添加一个Id。 Id的格式为“ - ###”。
151022
151022
151020
150922
150715
150911
151014
151021
151020
151019
151019
151019
151020
我需要它像这样打印
151022-001
151022-002
151020-001
150922-001
150715-001
150911-001
151014-001
151021-001
151020-002
151019-001
151019-002
151019-003
151020-002
我目前有这个代码,我发现并略有修改。如果我能让它开始计算-002处的唯一值,那么我相信这会解决它。
Option Explicit
Sub test()
Dim uniqueCounter As New Scripting.Dictionary
Dim counter As Long
Dim rowCount As Long
Dim identifer As String
rowCount = ActiveCell.CurrentRegion.Rows.Count 'Whatever code you want to put in to calculate the last row
For counter = 1 To rowCount
identifer = Sheet1.Cells(counter, 1) 'Put whatever number of combination of cells which the row unique here (maybe it's just the one)
If uniqueCounter.Exists(identifer) Then
uniqueCounter(identifer) = CLng(uniqueCounter(CStr(Sheet1.Cells(counter, 1)))) + 1
Sheet1.Cells(counter, 2) = identifer & "-00" & uniqueCounter(CStr(Sheet1.Cells(counter, 1)))
Else
uniqueCounter.Add identifer, "0"
Sheet1.Cells(counter, 2) = identifer
End If
Next counter
End Sub
目前显示的内容:
151022 151022
151022 151022-001
151020 151020
150922 150922
150715 150715
150911 150911
151014 151014
151021 151021
151020 151020-001
151019 151019
151019 151019-001
151019 151019-002
151020 151020-002
全部谢谢!
答案 0 :(得分:4)
我知道你要求vba,但是一个简单的公式会给你想要的输出。
在B1中:
=A1& "-" &TEXT(COUNTIF($A$1:A1,A1),"000")
并复制数据的范围。
如果你想要它在vba中;我会做这样的事情:
Sub test2()
Dim rng As Range
Dim rngcnt As Range
Dim firstrow As Long
Dim lastrow As Long
Dim columnNumber As Long
Dim ws As Worksheet
Set ws = Worksheets("Sheet15") 'change to your sheet
firstrow = 1 'change to your first row of data
columnNumber = 1 'change to the column number
With ws
lastrow = .Cells(.Rows.Count, columnNumber).End(xlUp).Row
For i = firstrow To lastrow
.Cells(i, columnNumber + 1) = .Cells(i, columnNumber) & "-" & Format(Application.WorksheetFunction.CountIf(.Range(.Cells(firstrow, columnNumber), .Cells(i, columnNumber)), .Cells(i, columnNumber)), "000")
Next i
End With
End Sub
有效地与上述公式相同。