Question

我在firebase中设计了这个扁平结构。

   {
    "groups": {
        "alpha": {
            "members": {
                "brinchen": true,
                "mchen": true
            },
            "name": "Alpha Tango"
        },
        "bravo": {
            "members": {
                "brinchen": true
            },
            "name": "Bravo Romeo"
        },
        "charlie": {
            "members": {
                "hmadi": true,
                "mchen": true
            },
            "name": "Charlie Whiskey"
        },
        "delta": {
            "name": "Delta Kilo"
        },
        "echo": {
            "name": "Echo Lima"
        },
        "foxtrot": {
            "name": "Foxtrot November"
        }

    },

    "users": {
        "brinchen": {
            "groups": {
                "alpha": true,
                "bravo": true
            },
            "name": "Byambyn Rinchen"
        },
        "hmadi": {
            "groups": {
                "charlie": true
            },
            "name": "Hamadi Madi"
        },
        "mchen": {
            "groups": {
                "alpha": true,
                "charlie": true
            },
            "name": "Mary Chen"
        }

    }
}

我有两个问题：

1-我想在Android中为这个json创建pojo类。我该怎么办？

2-对于ex，当我在用户json中更新用户名如“brinchen - ＆gt; john”时，如何将jhon与brinchen键中成员中的json组匹配？

Answer 1

你应该有 POJO来处理解析。例如，您可以/应该具有以下内容：

// Group or Team, you name it
public class Group {

    private String id;
    private String name;
    private List<String> members;

    public Group(){}

    public Group(JSONObject object) throws JSONException {
        this.id = object.getString("id");
        this.name = object.getString("name");
        members = new ArrayList<>();
        JSONArray list = object.getJSONArray("members");
        if(list!=null){
            for (int i = 0; i < list.length(); i++) {
                members.add(((JSONObject)list.get(i)).getString("name"));
            }
        }
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<String> getMembers() {
        return members;
    }

    public void setMembers(List<String> members) {
        this.members = members;
    }
}


public class User {

    private String id;
    private String name;
    private List<String> groups;

    public User(){}

    public User(JSONObject object) throws JSONException {
        this.id = object.getString("id");
        this.name = object.getString("name");
        groups = new ArrayList<>();
        JSONArray list = object.getJSONArray("groups");
        if(list!=null){
            for (int i = 0; i < list.length(); i++) {
                groups.add(((JSONObject)list.get(i)).getString("groupId"));
            }
        }
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<String> getGroups() {
        return groups;
    }

    public void setGroups(List<String> groups) {
        this.groups = groups;
    }
}

3）我不是完全喜欢Firebase，但是在Android上正常的JSON解析，你会做以下事情：

JSONObject teamInformation = Service.getTeamInformation();

ArrayList<Group> myGroup = new ArrayList<>();
JSONArray groupList = teamInformation.getJSONObject("groups");
 if(groupList!=null){
    for (int i = 0; i < groupList.length(); i++) {
        myGroup.add( new Group((JSONObject)groupList.get(i)) ); 
    }
}

ArrayList<User> myUsers = new ArrayList<>();
JSONArray userList = teamInformation.getJSONObject("users");
 if(userList!=null){
    for (int i = 0; i < userList.length(); i++) {
        myUsers.add( new User((JSONObject)userList.get(i)) ); 
    }
}

编辑：

基于Firebase文档，在 public void onDateChanged（DataSnapShot snap）上您可以通过执行以下操作将结果转换为JSON（我不确定您的结构，但它的类似这样 - 仅限于Groups JSON部分）：

public void onDateChanged(DataSnapShot snap) {
    for (DataSnapshot alert : alerts.getChildren()) {
        System.out.println(alert.child("id").getValue();
        System.out.println(alert.child("name").getValue();
        for (DataSnapshot recipient : alert.child("members").getChildren()) {
            System.out.println(recipient.child("name").getValue();
        }
    }
}

Firebase压扁结构并创建pojo android

1 个答案: