Question

这是自由代码阵营中的赋值，这是我的代码，对于第一次迭代时0的循环停止，它没有完成for循环的第一次迭代的原因是真的，我怎么能强制这个代码到完成循环以检查这个对象数组＆＃39;整体属性和价值观？

//Setup
var contacts = [
{
    "firstName": "Akira",
    "lastName": "Laine",
    "number": "0543236543",
    "likes": ["Pizza", "Coding", "Brownie Points"]
},
{
    "firstName": "Harry",
    "lastName": "Potter",
    "number": "0994372684",
    "likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
    "firstName": "Sherlock",
    "lastName": "Holmes",
    "number": "0487345643",
    "likes": ["Intriguing Cases", "Violin"]
},
{
    "firstName": "Kristian",
    "lastName": "Vos",
    "number": "unknown",
    "likes": ["Javascript", "Gaming", "Foxes"]
}
];


function lookUpProfile(firstName, prop) {
    debugger;

    // Only change code below this line
    for (var x = 0; x < contacts.length; x++) {
        if (!contacts[x].hasOwnProperty(prop)) {
            return 'No such property';
        }

        if (contacts[x].firstName != firstName) {
            return 'No such contact';
        }

        if (contacts[x].hasOwnProperty(prop) && contacts[x].firstName === firstName) {
            return prop;
        }
    }
    // Only change code above this line
}

// Change these values to test your function
lookUpProfile("Harry", "likes");

Answer 1

在循环内部，只有匹配时才应return。否则你应该继续：

当你到达循环的末尾时，这意味着没有匹配，你可以返回一个特定的错误值：

function lookUpProfile(firstName, prop) {
    debugger;

    // Only change code below this line
    for (var x = 0; x < contacts.length; x++) {
        if (contacts[x].hasOwnProperty(prop) && contacts[x].firstName === firstName) {
            return prop;
        }
    }
    return 'No such contact';
    // Only change code above this line
}

for循环没有完成整个对象长度的执行？

1 个答案: