Question

我有以下代码反序列化JSON文件，然后我需要遍历字典以获取最内层的值并分配给c＃对象：

public class Location
{
   public string Id { get; set; }
   public string Name { get; set; }
   public string Street { get; set; }
   public string City { get; set; }
   public string State { get; set; }
   public string Zip { get; set; }
}

string json = File.ReadAllText(@"C:\file.json");
JavaScriptSerializer ser = new JavaScriptSerializer();
var dict = ser.Deserialize<Dictionary<string, object>>(json);

foreach (var outer in dict)
{
    foreach (var middle in (Dictionary<string, object>)outer.Value)
    {
        foreach (var inner in (ArrayList)middle.Value)
        {
            foreach (var loc in (Dictionary<string, object>)inner)
            {
                var location = new Location();
                location.Id = ??;
                location.Name = ??;
                location.Street = ??;//...etc
            }
         }
    }
}

当我调试并逐步执行代码时，最内层循环的值显示：

loc {[ID, 601391]}  System.Collections.Generic.KeyValuePair<string,object>
    Key "ID"    string
    Value"601391"   object {string}

如何获取ID的值并将其分配给location.Id？

Answer 1

使用内部词典中包含的KeyValuePairs的Key和Value：

// outer loop
// middle loop
var location = new Location();
foreach (var loc in (Dictionary<string, object>)inner) {
    if (loc.Key == "ID") {
        location.Id = loc.Value.ToString();
        continue;
    }
    // if (loc.Key == "Name") ...
}

或使用索引器访问某些命名值（可能比循环遍历所有条目更快）。

// outer loop
// middle loop
var innerDict = (Dictionary<string, object>)inner;
var location = new Location();
if (innerDict.ContainsKey("ID")) {
    location.Id = innerDict["ID"];
}

Answer 2

您只需要转换值并使用反射来使代码更具可读性

var props = typeof(Location).GetProperties();

string json = File.ReadAllText(@"C:\file.json");
JavaScriptSerializer ser = new JavaScriptSerializer();
var dict = ser.Deserialize<Dictionary<string, object>>(json);

foreach (var outer in dict)
{
    foreach (var middle in (Dictionary<string, object>)outer.Value)
    {
        foreach (var inner in (ArrayList)middle.Value)
        {
            foreach (var loc in (Dictionary<string, object>)inner)
            {
                var location = new Location();
                var prop = props.FirstOrDefault(p => p.Name.ToUpper() == loc.Key.ToUpper());

                if (prop != null)
                {
                    prop.SetValue(location, loc.Value);
                }


            }
        }
    }
}

从嵌套字典中获取价值

2 个答案: