Question

我有一个像

这样的查询

  SELECT         COUNT(ShoppingProductFeature.ShoppingFeatureId) as countShow,ShoppingProductFeature.ShoppingFeatureId as valueId, ShoppingProductFeature.ShoppingParentFeatureId as attrId, ShoppingFeatureLanguage.Title as attrName, ShoppingFeatureLanguage_1.Title AS valueName 
   FROM            ShoppingFeatureLanguage INNER JOIN           ShoppingProductFeature INNER JOIN           ShoppingFeatureLanguage AS ShoppingFeatureLanguage_1 ON ShoppingProductFeature.ShoppingFeatureId = ShoppingFeatureLanguage_1.ShoppingFeatureId ON            ShoppingFeatureLanguage.ShoppingFeatureId = ShoppingProductFeature.ShoppingParentFeatureId INNER JOIN           ShoppingFeature ON ShoppingProductFeature.ShoppingFeatureId = ShoppingFeature.ShoppingFeatureId 
  INNER JOIN           Product ON ShoppingProductFeature.ProductId = Product.ProductId 
  INNER JOIN           Company ON Product.CompanyId = Company.CompanyId 
  GROUP BY ShoppingProductFeature.ShoppingFeatureId, ShoppingProductFeature.ShoppingParentFeatureId, ShoppingFeatureLanguage.Title, ShoppingFeatureLanguage_1.Title, ShoppingFeatureLanguage_1.LanguageId,                          ShoppingFeatureLanguage.LanguageId, ShoppingFeature.isConfirmed,Product.MoneyId,Product.TypeId , Company.GeoId , Product.ShoppinGroupId 
  HAVING        (ShoppingFeatureLanguage_1.LanguageId = 2) AND (ShoppingFeatureLanguage.LanguageId = 2) AND (ShoppingFeature.isConfirmed = 1)                           and (Product.TypeId = 11)  and Product.ShoppinGroupId like N'mn%'   and Company.GeoId like N'aa%' 
   ORDER BY countShow DESC

很明显我必须按 countShow 对其进行排序，我必须调用COUNT（ShoppingProductFeature.ShoppingFeatureId）进行选择，因为我无法将其添加到Order By

所以结果是这样的 enter image description here

如何在没有重复数据的情况下区分数据或对其进行排序

Answer 1

尝试下面的事情..

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