Question

我正计划在Firebase服务收到消息时启动通知，但是通知触发两次（一次准时，第二次可能是30分钟后）的问题是我的代码：

 sharedPreferences = PreferenceManager
            .getDefaultSharedPreferences(getApplicationContext());
    // Check if message contains a data payload.
    if (remoteMessage.getData().size() > 0) {
        Intent myIntent = new Intent(MyFirebaseMessagingService.this, MyAlarmService.class);
        pendingIntent = PendingIntent.getService(MyFirebaseMessagingService.this, 0, myIntent, 0);
        AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
        long currentTime = System.currentTimeMillis();

        int hour=sharedPreferences.getInt("Hour",9);
        int min=sharedPreferences.getInt("Min",0);
        Calendar calendar =  Calendar.getInstance();
        calendar.set(Calendar.HOUR_OF_DAY,hour);
        calendar.set(Calendar.MINUTE,min);



        alarmManager.set(AlarmManager.RTC_WAKEUP,calendar.getTimeInMillis() , pendingIntent);

这是MyAlarmService onStartCommand：

 public int onStartCommand(Intent intent, int flags, int startId) {


        Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(this);
        mBuilder.setSmallIcon(R.mipmap.ic_launcher);
        mBuilder.setContentTitle("Figures");
        mBuilder.setContentText("New Figures has been updated!");
        mBuilder.setAutoCancel(true);
        mBuilder.setSound(uri);
        Intent resultIntent = new Intent(this, LoginActivity.class);
        TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);
        stackBuilder.addParentStack(LoginActivity.class);
        stackBuilder.addNextIntent(resultIntent);
        PendingIntent resultPendingIntent = stackBuilder.getPendingIntent(0, PendingIntent.FLAG_UPDATE_CURRENT);
        mBuilder.setContentIntent(resultPendingIntent);
        NotificationManager mNotificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        mNotificationManager.notify(0, mBuilder.build());


    return super.onStartCommand(intent, flags, startId);
}

这是Vb.net发送通知功能：

Private Function sendNotification() As Integer
    Try
        Dim url As String = "https://fcm.googleapis.com/fcm/send"
        Dim tRequest As WebRequest = WebRequest.Create(url)

        tRequest.Method = "post"
        tRequest.ContentType = "application/json"
        Dim data = New With { _
            Key .[to] =myTopic, _
                Key .TTL = "109", _
            Key .data = New With { _
                Key .body = "Updated", _
                Key .title = "Daily" _
            } _
        }
        Dim jssons As String = Newtonsoft.Json.JsonConvert.SerializeObject(data)
        Dim bytearray As Byte() = Encoding.UTF8.GetBytes(jssons)
        tRequest.Headers.Add(String.Format("Authorization: key={0}", MyKey))
        tRequest.Headers.Add(String.Format("Sender: id={0}", MySenderId))
        tRequest.ContentLength = bytearray.Length
        tRequest.ContentType = "application/json"
        Using datastream As Stream = tRequest.GetRequestStream()
            datastream.Write(bytearray, 0, bytearray.Length)

            Using tresponse As WebResponse = tRequest.GetResponse

                Using dataStreamResponse As Stream = tresponse.GetResponseStream()

                    Using tReader As StreamReader = New StreamReader(dataStreamResponse)

                        Dim sResponseFromServer As String = tReader.ReadToEnd()

                        Log(sResponseFromServer, w)
                    End Using
                End Using

            End Using
        End Using

    Catch ex As WebException
        Log(ex.Message, w)
        Return ex.Status



    End Try
    Log("Notification sent", w)
    Return 200

End Function

有没有更好的方式发送通知？，AlarmManager中有任何问题吗？谢谢。

Answer 1

您的代码似乎没问题。但根据文件：

在应用的生命周期之外触发操作的常见方案是与服务器同步数据。在这种情况下，您可能会想要使用重复警报。但是，如果您拥有托管应用程序数据的服务器，则将Google云消息传递（GCM）与同步适配器结合使用是比AlarmManager更好的解决方案。同步适配器为您提供与AlarmManager相同的调度选项，但它为您提供了更大的灵活性。例如，同步可以基于＆＃34;新数据＆＃34;来自服务器/设备的消息（有关详细信息，请参阅运行同步适配器），用户的活动（或不活动），一天中的时间等。有关何时以及如何使用GCM和同步适配器的详细讨论，请参阅本页顶部的链接视频。

来源：Scheduling Repeating Alarms documentation

也许您可以尝试使用同步适配器。还要检查您是否收到了两次通知（我认为您不是）。或者检查警报是否设置为30分钟的重复周期。

希望这有帮助。

Answer 2

从MyAlarmService.onStartCommand（）返回START_NOT_STICKY，而不是调用super方法。 super方法返回START_STICKY，它会在系统被系统杀死后重启你的服务，重新触发通知。

另一个问题是，使用服务是否是一个好主意。我会尝试一个BroadcastReceiver，在你完成后不会继续运行。

Firebase onMessageReceived正在触发两次

2 个答案: