我想加入表A和表B,并显示每辆卡车的最新条目。
期望的输出
Truck | DateTime | Serial_Num | Lat | Long
1 | datestamp | 123 | 1 | -1
2 | datestamp | 456 | 2 | -2
使用联接查询
SELECT a.Truck b.Lat b.Long b.DateTime FROM TB as b INNER JOIN TA AS a a.Serial_Num=b.Serial_Num;
我试过这个,但它只给了我最近的参赛作品时间。
SELECT a.Truck b.Lat b.Long b.DateTime FROM TB as b INNER JOIN TA AS a a.Serial_Num=b.Serial_Num WHERE b.DateTime = (SELECT MAX(b.DateTime) FROM TB tb WHERE a.Truck_Num=Truck_Num);
答案 0 :(得分:2)
这将显示每辆卡车的最新项目。如果要显示的其他信息在所有行中相同,则可以将其放在group by子句中,否则则必须使用此结果进行连接
SELECT Serial_Num, MAX(DateTime) FROM TB GROUP BY Serial_Num;
如果数据不相等且您无法将其放在group by子句上,那么这是您必须要进行的连接
SELECT Truck_Num, Lat, Long, maxDateTime FROM TB as b
INNER JOIN TA AS a ON a.Serial_Num=b.Serial_Num
INNER JOIN (SELECT Serial_Num, MAX(DateTime) as maxDateTime
FROM TB GROUP BY Serial_Num) as c
ON b.Serial_Num=c.Serial_Num AND maxDateTime = DateTime
答案 1 :(得分:0)
它应该有效,你可以查看这个问题: Select only one row with max field with One-Many Relationship Table
SELECT
ta.Truck,
tb.Lat,
tb.Long,
MAX(tb.DateTime),
ta.Serial_Num as Serial_Num
FROM
TB as tb
INNER JOIN
TA as ta
ON (tb.Serial_Num = ta.Serial_Num)
GROUP BY
tb.Serial_Num