Question

描述

<小时/> 在 Powershell 中使用ConvertTo-Json，我正在尝试转换以下对象：

$richmessage = @{
    attachments = @(
        @{
            "mrkdwn_in" = @("text"; "pretext";);
            "title" = "title here";
            "title_link" = "http://somelinkhere/";
            "fallback" = "Summary of the attachment";
            "text" = "message";
            "color" = "red";       

        })      
}

write-host(ConvertTo-Json -InputObject $richmessage)

我希望得到这个输出：

{
    "attachments":  [
                    {
                        "text":  "message",
                        "fallback":  "Summary of the attachment",
                        "mrkdwn_in":  ["text" "pretext"],
                        "color":  "red",
                        "title":  "title here",
                        "title_link":  "http://somelinkhere/"
                    }
                ]
}

但实际输出是：

{
    "attachments":  [
                    {
                        "text":  "message",
                        "fallback":  "Summary of the attachment",
                        "mrkdwn_in":  "text pretext",
                        "color":  "red",
                        "title":  "title here",
                        "title_link":  "http://somelinkhere/"
                    }
                ]
}

备注

我希望"mrkdwn_in": "text pretext"为mrkdwn_in:["text", "pretext"]
如果我们采用$richmessage = @{ "mrkdwn_in" = @("text"; "pretext"); }，这将按预期生成数组，但是当数组嵌套时如下：$richmessage = @{ attachments = @( @{"mrkdwn_in" = @("text"; "pretext"); } ) };它结合了字符串。
我使用此功能向 Slack 发布一条富信息，并允许在附件中标记。（见this link）

问题

我怎样才能做到这一点？

Answer 1

尝试单独向对象添加数组值

$richmessage= $richmessage["attachments"][0]["mrkdwn_in"] = @("text", "pretext");

完整示例：

$richmessage = @{
    attachments = @(
        @{
            "mrkdwn_in" = ""; 
            "title" = "title here";
            "title_link" = "http://somelinkhere/";
            "fallback" = "Summary of the attachment";
            "text" = "message";
            "color" = "red";       

        })      
}

嵌套数组和对象未正确转换为json

1 个答案: