Question

我的网址查询字符串设计不佳，我无法轻易改变，例如

https://mysite/.shtml?source=999&promotype=promo&cmpid=abc--dfg--hif-_-1234&cm=qrs-stv-_wyx&aff=45628_THIS+IS+Test_Example

我需要从中提取元素，例如45628

目前我正在使用

document.URL.split(/aff=|_/)[5];

但是我不喜欢这个解决方案，因为如果URL结构的其他部分发生了很大变化，那么我的解决方案就会破解

相反，我想说的是

分裂＆＃34; aff =＆＃34;然后拆分＆＃34; _＆＃34;

有没有一种简单的方法可以做到这一点，寻找JS答案

Answer 1

Pretty sure you can do it like this:

document.URL.split("aff=")[1].split("_")[0];

Answer 2

I would start by splitting the string into tokens, if you can. Rather than working with foo=bar&fin=bin, break it down into [['foo', 'bar'], ['fin', 'bin]]. You can do that by splitting on the & and then the splitting each of those on the = character:

const data = 'source=999&promotype=promo&cmpid=abc--dfg--hif-_-1234&cm=qrs-stv-_wyx&aff=45628_THIS+IS+Test_Example';

console.log(data.split('&').map(it => it.split('=')));

Next, take the tokens you want and extract the leading digits:

const data = 'source=999&promotype=promo&cmpid=abc--dfg--hif-_-1234&cm=qrs-stv-_wyx&aff=45628_THIS+IS+Test_Example';

const tokens = data.split('&').map(it => it.split('='));
const [key,val] = tokens.find(([key]) => key === 'aff');
console.log(key, val.match(/[0-9]+/));

Answer 3

var url ='https://mysite/.shtml?source=999&promotype=promo&cmpid=abc--dfg--hif-_-1234&cm=qrs-stv-_wyx&aff=45628_THIS+IS+Test_Example';

var re = new RegExp（/ aff =（\ d +）/）; var ext = re.exec（url）[1]; 警报（EXT）

拆分术语上的字符串，然后拆分另一个术语

3 个答案: