Printf在printf中插入字符串值的附加换行符

Question

printf("It is currently %s's turn.\n", current->name);

我想知道为什么这会在％s之后打印出额外的换行符。我知道C中的字符串总是以\ 0结尾。如何在没有它的情况下打印它？

Answer 1

您的变量<DesiredConfigurationDigest xmlns="http://schemas.microsoft.com/SystemsCenterConfigurationManager/2009/07/10/DesiredConfiguration"> <SoftwareUpdateBundle AuthoringScopeId="Site_28E438B4-CB2F-43A2-AD6B-5A993F805BCB" LogicalName="SUM_4ca07bc3-8c95-4644-be17-040a3964a02a" Version="201"> <Annotation xmlns="http://schemas.microsoft.com/SystemsCenterConfigurationManager/2009/06/14/Rules"> <DisplayName Text="Security Update for Microsoft OneNote 2010 (KB3114885) 32-Bit Edition" /> <Description Text="A security vulnerability exists in Microsoft OneNote 2010 32-Bit Edition that could allow arbitrary code to run when a maliciously modified file is opened. This update resolves that vulnerability." /> </Annotation> ... 中有换行符，因此您需要删除该换行符。

current->name

这段代码将帮助您摆脱不必要的换行符。把它放在current->name[strcspn(current->name, "\n")] = '\0'; 之前。