Question

我必须编写一个代码，我需要将他们名字的人的电子邮件ID导入数据库中的excel表，但面临的问题是它显示我无效的文件，其中文件位于.csv格式，请帮忙，对这个概念不熟悉，请原谅我，如果我在某个地方出错了。

import.php

<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" enctype="multipart/form-data">
        <input type="file" name="sel_file" size="20" /><br />
        <input type="submit" name="submit" value="Submit" />
    </form>

                        <?php
    include ("connection.php");

    if(isset($_POST["submit"]))
    {
        $fname = $_FILES['sel_file']['tmp_name'];
        echo'Upload file name is'.$fname.' ';
        $chk_ext = explode(".",$fname);

    if(strtolower(end($chk_ext)) == "csv"){

        $filename = $_FILES['sel_file'] ['tmp_name'];
        $handle = fopen($filename, "r");

    while(($data = fgetcsv($handle, 1000, ",")) !== false)
        {
            $sql = "INSERT into import_email (vault_no, name, email) values ('".$_SESSION['vault_no']."', '$data[0]', '$data[1]')";
            mysql_query($sql) or die(mysql_error());
        }
        fclose($handle);
        echo "Successfully imported! ";
    }else{
        echo "Invalid file!";
    }
    }
?>

Answer 1

您正在使用临时名称而不是名称

   $_FILES['sel_file'] ['tmp_name'];

将其更改为：

   $_FILES['sel_file'] ['name'];

$_FILE['input_file']的例子是

[input_file] => Array
    (
        [name] => MyFile.jpg //<-------- This is the one you should use because it contains the extension (that you are checking for)
        [type] => image/jpeg
        [tmp_name] => /tmp/php/php6hst32 //<----------- this is the one you used 
        [error] => UPLOAD_ERR_OK
        [size] => 98174
    )

所以你的PHP部分应该是这样的：

    <?php
    include("connection.php");

    if (isset($_POST["submit"])) {
        $fname = $_FILES['sel_file']['name']; // Changed only this
        echo 'Upload file name is' . $fname . ' ';
        $chk_ext = explode(".", $fname);

        if (strtolower(end($chk_ext)) == "csv") {

            $filename = $_FILES['sel_file'] ['tmp_name'];
            $handle = fopen($filename, "r");

            while (($data = fgetcsv($handle, 1000, ",")) !== false) {
                $sql = "INSERT into import_email (vault_no, name, email) values ('" . $_SESSION['vault_no'] . "', '$data[0]', '$data[1]')";
                mysql_query($sql) or die(mysql_error());
            }
            fclose($handle);
            echo "Successfully imported! ";
        } else {
            echo "Invalid file!";
        }
    }
    ?>

将csv文件数据导入数据库

1 个答案: