我有以下代码来创建XML并阅读它, 我想要实现的是,根据它的ID删除特定节点。
班级employee.java -
package com.howtodoinjava.jaxb.examples.list;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "employee")
@XmlAccessorType (XmlAccessType.FIELD)
public class Employee
{
private Integer id;
private String firstName;
private String lastName;
private double income;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public double getIncome() {
return income;
}
public void setIncome(double income) {
this.income = income;
}
}
类Employees.java -
package com.howtodoinjava.jaxb.examples.list;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "employees")
@XmlAccessorType (XmlAccessType.FIELD)
public class Employees
{
@XmlElement(name="employee")
private List<Employee> employees = null;
private Integer size;
public List<Employee> getEmployees() {
return employees;
}
public void setEmployees(List<Employee> employees) {
this.employees = employees;
}
public Integer getSize() {
return size;
}
public void setSize(Integer size) {
this.size = size;
}
}
Class TestEmployeeMarshing.java -
package com.howtodoinjava.jaxb.examples.list;
import java.io.File;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Iterator;
import java.util.List;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
public class TestEmployeeMarshing
{
static Employees employees = new Employees();
static
{
employees.setEmployees(new ArrayList<Employee>());
Employee emp1 = new Employee();
emp1.setId(1);
emp1.setFirstName("John");
emp1.setLastName("Doe");
emp1.setIncome(10000.0);
Employee emp2 = new Employee();
emp2.setId(2);
emp2.setFirstName("Jane");
emp2.setLastName("Doe");
emp2.setIncome(20000.0);
Employee emp3 = new Employee();
emp3.setId(3);
emp3.setFirstName("Bacon");
emp3.setLastName("Butter");
emp3.setIncome(30000.0);
Employee emp4 = new Employee();
emp4.setId(4);
emp4.setFirstName("Pepparoni");
emp4.setLastName("Pizza");
emp4.setIncome(40000.0);
employees.getEmployees().add(emp1);
employees.getEmployees().add(emp2);
employees.getEmployees().add(emp3);
employees.getEmployees().add(emp4);
}
public static void main(String[] args) throws JAXBException
{
marshalingExample();
System.out.println("************************************************");
unMarshalingExample();
}
private static void unMarshalingExample() throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Employees.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
employees = new Employees();
employees = (Employees) jaxbUnmarshaller.unmarshal( new File("G:/xml/employees.xml") );
List<Employee> tempEmp= employees.getEmployees();
for (int i = 0; i < tempEmp.size(); i++) {
if(tempEmp.get(i).getId().equals(3)){
System.out.println("ID equals 3");
tempEmp.remove(i);
}
}
marshalingExample();
}
private static void marshalingExample() throws JAXBException
{
JAXBContext jaxbContext = JAXBContext.newInstance(Employees.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(employees, System.out);
jaxbMarshaller.marshal(employees, new File("G:/xml/employees.xml"));
}
}
我需要删除ID为1的节点并添加新节点。
答案 0 :(得分:3)
您最好使用它来分离从代码中读取数据的代码,例如:通过将代码的各个部分放在不同的方法中。此外,将数据传递给编组方法以便更容易重用而不是依赖static
employees
字段来传递数据会更方便。
List
实例中的Employees
可以像其他任何可修改的List
一样进行修改:
private static Employees unmarshalFromFile(String fileName) throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Employees.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
return (Employees) jaxbUnmarshaller.unmarshal(new File(fileName));
}
private static void marshalToFile(Employees data, String fileName) throws JAXBException
{
JAXBContext jaxbContext = JAXBContext.newInstance(Employees.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(data, new File(fileName));
}
public static void main(String[] args) throws JAXBException {
Employees data = unmarshalFromFile("G:/xml/employees.xml");
Integer removeId = 1;
data.getEmployees().removeIf((Employee emp) -> removeId.equals(emp.getId()));
Employee newEmployee = ...
data.getEmployees().add(newEmployee);
marshalToFile(data, "G:/xml/employees.xml");
}
在Java 8中添加了 removeIf
,但您也可以通过迭代列表在早期版本中执行此操作:
Iterator<Employee> iterator = data.getEmployees().iterator();
while (iterator.hasNext()) {
if (removeId.equals(iterator.next().getId())) {
iterator.remove();
}
}