Question

我是python的新手所以请原谅..我已经解析了一个XML文件并插入到sqlite中就好了但是我现在需要从多个具有相同名称的元素（通道类别）中获取文本值插入一个sql列，如

somecategory1, somecategory2

这就是我现在正在做的事情

elif elem.tag == "channel":
    cid = elem.get("id").replace("'", "")
    title = elem.findtext("display-name")
    chncategory = elem.findtext("channel-category")
    ..somecode..
    ..somecode..
    result = Channel(cid, title, chncategory, logo, streamUrl, visible)

然后我称之为

c.execute('INSERT OR IGNORE INTO channels(id, title, chncategory, logo, stream_url, visible, weight, source) VALUES(?, ?, ?, ?, ?, ?, (CASE ? WHEN -1 THEN (SELECT COALESCE(MAX(weight)+1, 0) FROM channels WHERE source=?) ELSE ? END), ?)',
                    [channel.id, channel.title, channel.chncategory, channel.logo, channel.streamUrl, channel.visible, channel.weight,
                     self.source.KEY, channel.weight, self.source.KEY])

工作正常..但它只抓取FIRST通道类别元素，我需要抓住它们并添加到该列中，使其显示为

somecategory1, somecategory2, etc

我的xml看起来像这样

<tv info="blahblah">
  <channel id="channel1">
    <display-name lang="en">channel1</display-name>
    <icon src="somewhere.png" />
    <url>http://someurl.com</url>
    <channel-category>somecategory1</channel-category>
    <channel-category>somecategory2</channel-category>
  </channel>
</tv>

我如何才能完成这项工作，而不只是抓住第一个值并将其放入列中，让它抓住所有并插入到那一列？

Answer 1

怎么样，而不是

chncategory = elem.findtext("channel-category")

您使用：

In [5]: chncategory = ', '.join(map(lambda x: x.text, elem.findall("channel-category")))

In [6]: chncategory
Out[6]: 'somecategory1, somecategory2'

python解析具有多个元素的XML并插入到sqlite中

1 个答案: