Question

所以，我正在为madlibs制作一个Python 3小程序。到目前为止，我有它，所以它读取一个文本文件，从中提取一个随机的故事，并将该故事分成一个列表，以便通过它进行搜索。一切都很好。我将这些故事格式化，以便在需要单词时使用（名词），（副词），（名称）等等。但是，我在替换这些字符串时遇到了一些问题。这是一个例子：

>>> for i in range(0,len(poss)):
...  if '(' in poss[i]: poss[i] = input('{0}: '.format(poss[i].replace('(','').replace(')','')))
...
noun: monster
name.: Strange
name: Strange
adjective: yellow
noun!: eatery
place.
: Times Square
>>> poss = ' '.join(poss)
>>> print(poss)
                               Back to the Future

Marty was an innocent, young monster and made friends with the local scientist,
Doc Strange Doc Strange was a bit off, but he was one yellow genius. One day,
he told Marty that he had an invented a eatery Of course, Marty had to see it
in action. Late that night, they met at Times Square

它搜索每个对象中的＆＃39;（＆＃39;字符，然后用单词替换整个对象。它不会保留可能涉及的标点符号。此外，你可以看到标点符/换行符留在调用input()时显示。如何有效地替换括号中包含的子串？

供参考，以下是从文件中提取的原始文本：

                               Back to the Future

Marty was an innocent, young (noun) and made friends with the local scientist,
Doc (name). Doc (name) was a bit off, but he was one (adjective) genius. One day,
he told Marty that he had an invented a (noun)! Of course, Marty had to see it
in action. Late that night, they met at (place).

我的预期结果是：

                               Back to the Future

Marty was an innocent, young monster and made friends with the local scientist,
Doc Strange. Doc Strange was a bit off, but he was one yellow genius. One day,
he told Marty that he had an invented a eatery! Of course, Marty had to see it
in action. Late that night, they met at Times Square.

Answer 1

要解决您的方法存在的问题，我需要查看完整的代码，但我还有其他建议。

你实际上可以在这里使用正则表达式，这允许在一行（几乎）中进行替换。

In [1]: import re

In [2]: story = '''                               Back to the Future
   ...: 
   ...: Marty was an innocent, young (noun) and made friends with the local scientist,
   ...: Doc (name). Doc (name) was a bit off, but he was one (adjective) genius. One day,
   ...: he told Marty that he had an invented a (noun)! Of course, Marty had to see it
   ...: in action. Late that night, they met at (place).'''

In [3]: def replace(match):
   ...:     return input('{}: '.format(match.group()))
   ...: 

In [4]: print(re.sub('\((noun|name|adjective|place)\)', replace, story))
(noun): monster
(name): Strange
(name): Strange
(adjective): yellow
(noun): eatery
(place): Times Square
                               Back to the Future

Marty was an innocent, young monster and made friends with the local scientist,
Doc Strange. Doc Strange was a bit off, but he was one yellow genius. One day,
he told Marty that he had an invented a eatery! Of course, Marty had to see it
in action. Late that night, they met at Times Square.

re.sub()接受一个可调用的替换，我们用它来调用input()并从匹配中提取提示。

编辑以匹配括号中的任何词组，您只需更改模式，例如：

print(re.sub('\(([^()]*)\)', replace, story))

Answer 2

text = """Marty was an innocent, young (noun) and made friends with the local scientist,
Doc (name). Doc (name) was a bit off, but he was one (adjective) genius. One day,
he told Marty that he had an invented a (noun)! Of course, Marty had to see it
in action. Late that night, they met at (place)."""


match = ['monster', 'Strange', 'Strange', 'yellow', 'eatery', 'Times Square']

splitted = text.split()

for i, item in enumerate(splitted):
    if '(' in item:
        matched = match.pop(0)
        if not item.endswith(')'):
            matched = '{}{}'.format(matched, item[:-1])
        splitted[i] = matched

print ' '.join(splitted)

Answer 3

好的，为了解决我只想要一次询问每个相同项目的问题，我不得不重写一点。我还在使用@Lex提供的正则表达式，所以感谢他。但是，我不再使用他的re.sub()方法。

import re
l1 = re.findall('\(([^()]*)\)',story)
l2 = []
for i in l1:
 if i not in l2:
  l2.append(i)
for i in l2:
 substr = '({})'.format(i)
 word = input('{}: '.format(i))
 story = story.replace(substr,word)


print(story)

findall()函数在括号＆＃34;之间找到与＆＃34;的正则表达式匹配的所有实例。并构建一个初始列表。然后，我遍历该列表并将每个唯一标记放入新列表中以消除重复。我遍历新的令牌列表，并用提示的输入替换每个匹配。这正是我想要的applet，因为它消除了重复的提示。

用用户输入

3 个答案: