Question

我需要以编程方式浏览网站。仅WebView只有图形输出所以，我想在后台加载一个html，填写一个字段并执行点击提交按钮 P. S.为什么需要我。 - 因为我需要覆盖网站登录表单，但我无法通过HttpsURLConnection模拟html表单发布方法。我认为在cookie中存在这个问题并且重新发布它但它没有帮助。

ADDED
如果有人可以帮助HttpsURLConnection，那么我会尝试使用https://www.instagram.com/accounts/login/?force_classic_login=&next=/oauth/authorize/%3Fclient_id%CLIENT_ID%26redirect_uri%3Dhttps%3A//test.com/instagram/auth%26response_type%3Dcode链接。我可以在Chrome中打开此链接，但HttpsURLConnection在日志中写入未找到该文件。我在网上是noobie所以我真的无法理解问题我从Instagram登录页面的html中获取此链接。

这是我向Instagram服务发送登录名和密码的代码：

public static String requestCode(final String username, final String password) throws IOException {
    Values args = new Values(3);
    args.add(KEY_CLIENT_ID, CLIENT_ID);
    args.add(KEY_RESPONSE_TYPE, "code");
    args.add(KEY_REDIRECT_URI, REDIRECT_URI);
    HttpsURLConnection connection = new HttpsRequest(URL_AUTH)
        .setCacheMode(CacheMode.DISABLED)
        .setRequestArguments(args)
        .build();
    Map<String, List<String>> map = connection.getHeaderFields();
    List<String> cookies = map.get("Set-Cookie");
    CookieManager cookieManager = new CookieManager();

    for (String cookie : cookies) {
        cookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
    }

    final String csrfToken = getCsrfToken(cookies);
    connection.disconnect();

    if (!TextUtils.isEmpty(csrfToken)) {
        Values properties = new Values(1);
        properties.add("Cookie",
            TextUtils.join(";", cookieManager.getCookieStore().getCookies()));
        Values bodyArgs = new Values(3);
        bodyArgs.add("csrfmiddlewaretoken", csrfToken);
        bodyArgs.add("username", username);
        bodyArgs.add("password", password);
        final String additionalUrl = "?" + KEY_CLIENT_ID + "=" + CLIENT_ID + "&"
            + KEY_REDIRECT_URI + "=" + REDIRECT_URI + "&"
            + KEY_RESPONSE_TYPE + "=code";
        final String url = URL_LOGIN + "?force_classic_login=&next=/oauth/authorize/"
            + URLEncoder.encode(additionalUrl, "UTF-8");
        connection = new HttpsRequest(url)
            .setRequestMethod(HttpsRequest.POST)
            .setRequestProperties(properties)
            .setBodyArguments(bodyArgs)
            .setCacheMode(CacheMode.DISABLED)
            .build();
        final String answer = ConnectionUtils.readToString(connection.getInputStream());
        connection.disconnect();
        Log.d(TAG, "Answer: " + answer);
    }

    return null;
}

我用过的

Instagram docs。

如何以编程方式浏览网站

0 个答案: