Question

我的javascript代码中有以下部分，其中我想使用包含信息的变量来填充数据源而不是写下信息。我有办法吗？

...
resources: [
                {
                    field: "IdDepartament",
                    title: "Departament",
                    name: "Departaments", allowMultiple: false,
                    resourceSettings: {
                        dataSource: [
                            //{ text: "Sales", id: 1, groupId: 1, color: "#100000" }, { text: "Programming", id: 2, groupId: 1, color: "#199999" }, { text: "Human Resources", id: 3, groupId: 1, color: "#299998" }, { text: "Support", id: 4, groupId: 1, color: "#399997" }
                        ],
                        text: "text", id: "id", groupId: "groupId", color: "color"
                    }
                },
...

我使用ajax生成要在dataSource上显示的信息，并将其保存为javascript变量并在console.log上显示信息，以确保我收到正确的信息。

修改：
我想做这样的事情：

var departments = ({ text: "Sales", id: 1, groupId: 1, color: "#100000" }, { text: "Programming", id: 2, groupId: 1, color: "#199999" }, { text: "Human Resources", id: 3, groupId: 1, color: "#299998" }, { text: "Support", id: 4, groupId: 1, color: "#399997" });

在我指定dataSource的地方使用该变量

Answer 1

是的，可以分配包含信息的变量来填充dataSource，而不是直接写下信息，如下所示，

// variable with resource data information
var resourceData = [
                    { text: "Nancy", id: 1, groupId: 1, color: "#f8a398" },
                    { text: "Steven", id: 3, groupId: 2, color: "#56ca85" },
                    { text: "Michael", id: 5, groupId: 1, color: "#51a0ed" }
]

resources: [
                  {
                      field: "ownerId",
                      title: "Owner",
                      name: "Owners", allowMultiple: true,
                      resourceSettings: {
                          dataSource: resourceData, // assigning the variable to resource data source
                          text: "text", id: "id", groupId: "groupId", color: "color"
                      }
                  }]

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