我有一个使用Spring Boot和Jetty的简单应用程序。我有一个简单的控制器返回一个具有Java 8 ZonedDateTime
:
public class Device {
// ...
private ZonedDateTime lastUpdated;
public Device(String id, ZonedDateTime lastUpdated, int course, double latitude, double longitude) {
// ...
this.lastUpdated = lastUpdated;
// ...
}
public ZonedDateTime getLastUpdated() {
return lastUpdated;
}
}
在我的RestController
我只是:
@RequestMapping("/devices/")
public @ResponseBody List<Device> index() {
List<Device> devices = new ArrayList<>();
devices.add(new Device("321421521", ZonedDateTime.now(), 0, 39.89011333, 24.438176666));
return devices;
}
我期待ZonedDateTime
根据ISO格式进行格式化,但我得到的是类的整个JSON转储:
"lastUpdated":{"offset":{"totalSeconds":7200,"id":"+02:00","rules":{"fixedOffset":true,"transitionRules":[],"transitions":[]}},"zone":{"id":"Europe/Berlin","rules":{"fixedOffset":false,"transitionRules":[{"month":"MARCH","timeDefinition":"UTC","standardOffset":{"totalSeconds":3600,"id":"+01:00","rules":{"fixedOffset":true,"transitionRules":[],"transitions":[]}},"offsetBefore":{"totalSeconds":3600,"id":"+01:00","rules":{"fixedOffset":true,"transitionRules":[],"transitions":[]}},"offsetAfter":{"totalSeconds":7200,"id":"+02:00", ...
我只有spring-boot-starter-web
个应用,使用spring-boot-starter-jetty
并排除spring-boot-starter-tomcat
。
杰克逊为什么在Spring Boot中表现得像这样?
**更新**
对于那些寻找完整的分步指导如何解决这个问题的人,我在问到这个问题后发现了这个: http://lewandowski.io/2016/02/formatting-java-time-with-spring-boot-using-json/
答案 0 :(得分:36)
有一个图书馆jackson-datatype-jsr310。试试吧。
此库涵盖新的日期时间API,并包含ZonedDateTime
的序列化程序。
您只需添加JavaTimeModule
:
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());
更新
要将日期时间转换为ISO-8601
字符串,您应该禁用WRITE_DATES_AS_TIMESTAMPS
功能。您可以通过覆盖ObjectMapper
bean或使用application properties:
spring.jackson.serialization.WRITE_DATES_AS_TIMESTAMPS = false
答案 1 :(得分:2)
如果您不依赖SpringBoot的自动配置功能-您不向配置文件中提供 this.markerForm = this.fb.group({
description: ['', Validators.required ]
});
属性-或出于任何原因您手动创建spring.jackson.serialization.WRITE_DATES_AS_TIMESTAMPS = false
实例。您可以通过编程方式禁用此功能,如下所示:
ObjectMapper
这是给杰克逊ObjectMapper m = new ObjectMapper();
m.disable(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS);
答案 2 :(得分:1)
上面已经提到了答案,但我认为它缺少一些信息。对于那些希望以多种形式解析Java 8时间戳的人(不仅仅是ZonedDateTime)。您的POM中需要jackson-datatype-jsr310
的最新版本,并注册了以下模块:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.registerModule(new JavaTimeModule());
objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
测试此代码
@Test
void testSeliarization() throws IOException {
String expectedJson = "{\"parseDate\":\"2018-12-04T18:47:38.927Z\"}";
MyPojo pojo = new MyPojo(ZonedDateTime.parse("2018-12-04T18:47:38.927Z"));
// serialization
assertThat(objectMapper.writeValueAsString(pojo)).isEqualTo(expectedJson);
// deserialization
assertThat(objectMapper.readValue(expectedJson, MyPojo.class)).isEqualTo(pojo);
}
请注意,您可以在Spring或dropwizard中全局配置对象映射器以实现此目的。我还没有找到一种干净的方法来在不注册自定义(反)序列化器的情况下将其作为字段上的注释。
答案 3 :(得分:0)
对于杰克逊2.10
及更高版本,
父pom.xml
<!-- https://github.com/FasterXML/jackson-bom -->
<dependencyManagement>
<dependency>
<groupId>com.fasterxml.jackson</groupId>
<artifactId>jackson-bom</artifactId>
<version>2.10.3</version>
<type>pom</type>
<scope>import</scope>
</dependency>
</dependencyManagement>
模块pom.xml
<!-- https://github.com/FasterXML/jackson-modules-java8 -->
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
JsonMapper的创建,可能在您的@Configuration
类中
@Bean
public JsonMapper jsonMapper() {
return JsonMapper.builder()
.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false)
.addModule(new JavaTimeModule())
.build();
}
进一步阅读: