使用SELECT菜单动态更新数据库

Question

感谢您的所有建议！我正在列出未设置为＆＃34;当月和＃34;进入下拉菜单/选择菜单，以便将其他月份设置为可用于操作。我得到了该列表，但它填充了下拉列表，但是没有将该值传递给更新。我非常困惑或者缺少非常小的东西。

以下是查询：

if (isset($_POST['addMonth'])) {
   $addmonth = $_POST['addmonth'];
   //open additional months
   $query_open_additional = "UPDATE reimbmonths SET reimb_open = 1 WHERE monthname = '$addmonth' ";
   $query_current = "SELECT * FROM reimbmonths WHERE reimb_open = 1";
   $result_current = mysql_query($query_current) or die ('Query failed: ' . mysql_error() . "<br />\n$sql");
   $num_current = mysql_num_rows($result_current);

   echo "Added another month: " . $addmonth;
}

这是HTML / PHP：

<h3>Open additional months</h3>
<form id="add-months" action="" method="post" onsubmit="window.location.reload() onchange="addMonth();"">
    <select name="addmonth" id="addmonth">
        <option <? if (empty($_POST["addmonth"])) { echo 'selected';} ?> disabled> --- Choose a Month --- </option>
        <?
        $i = 0;
        while ($i < $num_months) {
            $month_to_add = mysql_result($result_select_closed,$i,"monthname");
        ?>
        <option value="<? $month_to_add ?>" <? if($_POST["addmonth"] === '$month_to_add') { echo 'selected';} ?>><? echo ucwords($month_to_add) ?></option>
        <? 
        $i++;
        }
        ?>
    </select>
    <input class="submit_btn" type="submit" name="addMonth" value="Set Month"/>
</form>