我有一个弹出框,右上角有一个关闭按钮,看起来像这样。 问题是当水平滚动打开并向右滚动时,它会将位置更改为框的中心,就像这样。如何修复弹出框(div)右上角的按钮?
按钮位置我的css
.pop > span {
cursor: pointer;
color: red;
position: absolute;
top: 4%;
right: 4%;
}
.pop {
display: none;
position: absolute;
top: 10%;
left: 20%;
width: 500px;
height: 400px;
}
我的HTML
<div class="container pop ui-widget-content"><span><i aria-hidden="true" class="fa fa-times fa-lg"></i></span>
...
</div>
我尝试将css更改为此,但它只是将按钮放在主页面中的弹出框之外,这不是我想要做的事情
.pop > span {
cursor: pointer;
color: red;
position: fixed;
top: 10%;
right: 10%;
}
答案 0 :(得分:2)
.pop {
position:relative;
}
.pop > span {
position:absoltute;
top:10px;
right:10px;
}
答案 1 :(得分:0)
你是对的,浮动不会像那样工作但here is how I make it work fiddle:
HTML:
<div class="popCont">
<span><i aria-hidden="false" class="fa fa-times fa-lg">X</i></span>
<div class="container pop ui-widget-content">
<div id="codeDiv">this is a test this is a test this is a test this is a test this is a test this is a test this is a test this is a test this is a test this is a test this is a test this is a test</div>
<p>
This is a test
5456456456456456 64564gf56d4sgf56 sr4g56dfs4g56df4g6 er5g4df5s64g5df4g56 deg465es4g5d4s56g4d5s6g46dsg456 w4g56ds5gdf5sg56ds4 w56g45ds4g5sg4sd4g sd4g56d4s56g4df5s6g4 sgdfsgdfgh!!!
</p>
</div>
</div>
CSS:
.popCont > span {
padding 15px;
margin-left: 97%;
margin-top: 1%;
cursor: pointer;
color: red;
}
.popCont{
position: absolute;
top: 10%;
left: 20%;
width: 500px;
height: 400px;
border: 2px solid blue;
}
.pop {
display: block;
overflow: hidde;
overflow-x: scroll;
}
#codeDiv{
width: 450px;
}
答案 2 :(得分:0)
感谢大家的帮助。我最后通过跟随这个小提琴http://jsfiddle.net/84cyupb0/1/来修复它,并添加了另一个div来包装内部div。
.outer {
position: absolute;
width: 98%;
border:1px solid red;
}
.relative {
position: relative;
}
.inner {
height:200px;
overflow-y:scroll;
}
.close {
position: absolute;
top: 10px;
right: 10px;
}