Question

我正在尝试将数据从外部API导入到我自己的MySQL服务器。但问题是，我想从特定字段获取值，但它只是将其设置为1或2。

这是我尝试导入的JSON对象之一的示例：

{
_index: "events",
_type: "event",
_id: "2290", **<-- THIS IS THE VALUE I WANT TO GET**
_score: null,
fields: {
genres: [
"["World Music","Dance","Theater"]"
],
name: [
"Festival Spoffin 2016"
],
start: [
"2016-08-25T11:00:00+0000"
],
venue.location: [
5.387848,
52.1563989
],
description: [
"TEXT"
],
logo: [
"URL"
],
header: [
"URL"
],
venue.country: [
"Nederland"
],
venue.city: [
"Amersfoort"
]
},
sort: [
1472122800000
]
},

但是当我运行的查询运行良好时，这里是代码：

<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$jsondata = file_get_contents('https://hugo.events/genre/dance/next/900/1');
$data     = json_decode($jsondata, true);
$uname    = '****';
$upass    = '****';
$dbh      = new PDO('mysql:host=localhost;dbname=wtd', $uname, $upass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql  = "TRUNCATE TABLE dance";
$stmt = $dbh->prepare($sql);
$stmt->execute();
if (!$stmt) {
    echo "Statement failed";
} else {
    $statement = $dbh->prepare("INSERT INTO dance(event_id, event_name, event_date, event_country, event_genres, event_desc, event_logo, event_header_pic)
    VALUES(:eventid, :name, :date, :country, :genres, :desc, :logo, :header_pic)");
    $id        = $data[1]['hits']['hits'][1]['_id'];
    foreach ($data[1]['hits']['hits'] as $row) {
        $statement->execute(array(
            "eventid" => $row['_id'][0], **<-- THIS IS THE COLUMN I WANT TO PUT IT IN** 
            "name" => $row['fields']['name'][0],
            "date" => $row['fields']['start'][0],
            "country" => isset($row['fields']['venue.country']) ? $row['fields']['venue.country'][0] : '',
            "genres" => $row['fields']['genres'][0],
            "desc" => $row['fields']['description'][0],
            "logo" => $row['fields']['logo'][0],
            "header_pic" => $row['fields']['header'][0]
        ));
    }
        echo "Data inserted into dance table";
}

当我将其作为JSON回显时它只返回这个，并且在phpMyAdmin中也显示相同的内容：

{
id: "1",
event_id: "2", **<-- THIS IS SUPPOSED TO BE THE VALUE OF _ID**
event_name: "Festival Spoffin 2016",
event_date: "2016-08-25T11:00:00+0000",
event_country: "Nederland",
event_genres: "["World Music","Dance","Theater"]",
event_desc: "TEXT",
event_logo: "URL",
event_header_pic: "URL"
},

Answer 1

id是一个整数，而不是一个数组，所以最后你不需要额外的[0]。否则，你只是得到整数中的第一个数字。

"eventid" => $row['_id'],

无法从JSON文件到MySQL服务器获得正确的价值

1 个答案: