从普通字符串ruby获取字符串数组

Question

我有一个如下所示的字符串模式，

 => "text1 http://www.domain.com/experiment_B_setup_diagram_image.png\n\nExperiments text2 http://www.domain.com/experiment_C_setup_diagram_image.png \nexperiment text3 http://www.domain.com/experiment_A_plotted_cha
rt.png"

我想要分开url然后逐个字符串，输出应该是，

> ["text1",
> "http://www.domain.com/experiment_B_setup_diagram_image.png",
> "\n\nExperiments", "text2",
> "http://www.domain.com/experiment_C_setup_diagram_image.png",
> "\nexperiment", "text3",........]

像单独的url及其前面或后续的字符串作为数组...有人可以帮助我吗？

Answer 1

尝试使用：

.split(/\s|\n+/)

例如：

text="text1 http://www.domain.com/experiment_B_setup_diagram_image.png\n\nExperiments text2 http://www.domain.com/experiment_C_setup_diagram_image.png \nexperiment text3 http://www.domain.com/experiment_A_plotted_chart.png"
text.split(/\s|\n/)

返回：

["text1", "http://www.domain.com/experiment_B_setup_diagram_image.png", "", "Experiments", "text2", "http://www.domain.com/experiment_C_setup_diagram_image.png", "", "experiment", "text3", "http://www.domain.com/experiment_A_plotted_chart.png"]

Answer 2

只要您放弃换行符（\ n）就可以了，您可以先将它们转换为空格，然后简单地拆分空格：

x = "text1 http://www.domain.com/experiment_B_setup_diagram_image.png\n\nExperiments text2 http://www.domain.com/experiment_C_setup_diagram_image.png \nexperiment text3 http://www.domain.com/experiment_A_plotted_chart.png"
x.tr("\n", " ").split(" ")