Question

我有一个类似于以下的表

sno | booking_id | room_type | gender | age | amount | days
1   | 2016JUL001 | AC        | Male   | 25  | 1000   | 15 
2   | 2016JUL001 | AC        | Male   | 42  | 1000   | 15 
3   | 2016JUL001 | AC        | Male   | 28  | 1000   | 15 
4   | 2016JUL010 | N AC      | Female | 45  | 1000   | 15 
5   | 2016JUL010 | N AC      | Female | 46  | 1000   | 15 
6   | 2016JUL005 | N AC      | Male   | 28  | 1000   | 15 
7   | 2016JUL005 | N AC      | Female | 35  | 1000   | 15 
8   | 2016JUL009 | AC        | Female | 26  | 1000   | 15 
9   | 2016JUL009 | AC        | Female | 25  | 1000   | 15

......等等

预期输出[如果我想得到性别='女性']

sno | booking_id | room_type | gender | age | amount | days
4   | 2016JUL010 | N AC      | Female | 45  | 1000   | 15 
5   | 2016JUL010 | N AC      | Female | 46  | 1000   | 15
8   | 2016JUL009 | AC        | Female | 26  | 1000   | 15 
9   | 2016JUL009 | AC        | Female | 25  | 1000   | 15

预期输出[如果我想获得性别='男性']

sno | booking_id | room_type | gender | age | amount | days
1   | 2016JUL001 | AC        | Male   | 25  | 1000   | 15 
2   | 2016JUL001 | AC        | Male   | 42  | 1000   | 15 
3   | 2016JUL001 | AC        | Male   | 28  | 1000   | 15

预期输出[如果我想获得性别='男性'和性别='女性']

sno | booking_id | room_type | gender | age | amount | days
6   | 2016JUL005 | N AC      | Male   | 28  | 1000   | 15 
7   | 2016JUL005 | N AC      | Female | 35  | 1000   | 15

注意：我想要3个独立的个人查询来获得上述输出

提前致谢

Answer 1

首先查询：

SELECT sno, booking_id, room_type, gender, age 
FROM customer_data 
WHERE booking_id IN ( SELECT booking_id FROM customer_data 
                      WHERE gender='female' AND age>0 and RIGHT(booking_id,1) <> '1' 
                      GROUP BY booking_id HAVING COUNT(*) > 1 ) 
ORDER BY booking_id ASC, age ASC

第二：

SELECT sno, booking_id, room_type, gender, age 
FROM customer_data 
WHERE booking_id IN ( SELECT booking_id FROM customer_data 
                      WHERE gender='male' AND age>0 
                      GROUP BY booking_id HAVING COUNT(*) > 1 ) 
ORDER BY booking_id ASC, age ASC

第三名：

SELECT sno, booking_id, room_type, gender, age 
FROM customer_data 
WHERE booking_id IN ( SELECT booking_id FROM customer_data 
                      WHERE gender IN('male','female') AND age>0 
                      GROUP BY booking_id HAVING COUNT(distinct gender) = 2 ) 
ORDER BY booking_id ASC, age ASC

如果在前两个中你只想要只有1个性别的booking_id，请添加到having子句：

AND COUNT(distinct gender) = 1

Answer 2

您的架构似乎有些缺陷。不过，这里需要考虑一下......

SELECT booking_id
     , COUNT(DISTINCT gender) x 
  FROM customer_data 
 WHERE gender IN ('Male','Female') <-- not strictly necessary if there are only two genders.
 GROUP 
    BY booking_id;

Answer 3

经过多次尝试，我能够获得我想要的数据

查询[＆＃39;女性＆＃39;]

SELECT sno, bd.booking_id, bd.room_type, bd.gender, bd.age 
FROM customer_data bd 
INNER JOIN ( 
    SELECT booking_id, GROUP_CONCAT(DISTINCT gender) AS g 
    FROM customer_data 
    WHERE gender!='' AND age>0 
    GROUP BY booking_id 
    HAVING COUNT(booking_id) > 1 
    ORDER BY booking_id ASC, gender DESC 
) cbd 
WHERE cbd.booking_id = bd.booking_id AND cbd.g = 'Female'

查询[＆＃39;男＆＃39;]

SELECT sno, bd.booking_id, bd.room_type, bd.gender, bd.age 
FROM customer_data bd 
INNER JOIN ( 
    SELECT booking_id, GROUP_CONCAT(DISTINCT gender) AS g 
    FROM customer_data 
    WHERE gender!='' AND age>0 
    GROUP BY booking_id 
    HAVING COUNT(booking_id) > 1 
    ORDER BY booking_id ASC, gender DESC 
) cbd 
WHERE cbd.booking_id = bd.booking_id AND cbd.g ='Male'

查询[＆＃39;男性和女性＆＃39;]

SELECT sno, bd.booking_id, bd.room_type, bd.gender, bd.age 
FROM customer_data bd 
INNER JOIN ( 
    SELECT booking_id, GROUP_CONCAT(DISTINCT gender ORDER BY gender DESC) AS g 
    FROM customer_data 
    WHERE gender!='' AND age>0 
    GROUP BY booking_id 
    HAVING COUNT(booking_id) > 1 
    ORDER BY booking_id ASC, gender DESC 
) cbd 
WHERE cbd.booking_id = bd.booking_id AND cbd.g = 'Male,Female'

MySQL - 由同一个表中的多个列分组

3 个答案: