无法从Android应用程序到已部署的PHP服务器进行REST API调用?

时间:2016-08-22 06:21:20

标签: php android google-app-engine phpmyadmin google-cloud-sql

我无法连接到托管MySQL数据库的Google Cloud PHP服务器。这是我向PHP服务器发送通知的代码。

NotificationInstanceService.java

public class NotificationInstanceService extends FirebaseInstanceIdService {
    private static final String TAG = "NotificationInstance";

    @Override
    public void onTokenRefresh() {

        //Getting registration token
        String refreshedToken = FirebaseInstanceId.getInstance().getToken();

        //Displaying token on logcat
        Log.d(TAG, "Refreshed token: " + refreshedToken);

        sendRegistrationToServer(refreshedToken);

    }

    private void sendRegistrationToServer(String token) {
        //You can implement this method to store the token on your server
        //Not required for current project
        OkHttpClient client = new OkHttpClient();
        //Create the request body
        RequestBody body = new FormBody.Builder().add("Token", token).build();
        //Know where to send the request to
        Request request = new Request.Builder().url("<app server url>/register.php")
                .post(body)
                .build();
        //Create
        try {
            client.newCall(request).execute();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}

这似乎正确地进行了,并且似乎没有抛出任何堆栈跟踪。然后,当我部署我的PHP服务器时,我创建了以下文件:

的app.yaml:

application: <app server url>
service: default
runtime: php55
api_version: 1
version: alpha-001

handlers:

- url: /(.+\.(ico|jpg|png|gif))$
  static_files: \1
  upload: (.+\.(ico|jpg|png|gif))$
  application_readable: true

- url: /(.+\.(htm|html|css|js))$
  static_files: \1
  upload: (.+\.(htm|html|css|js))$
  application_readable: true

- url: /(.+\.php)$
  script: \1
  login: admin

- url: /.*
  script: index.php
  login: admin

- url: /.*
  script: register.php
  login: admin

的config.inc.php:

<?php 
$cfg['blowfish_secret'] = '<Secret>'; /* YOU MUST FILL IN THIS FOR COOKIE AUTH! */

/*
 * Servers configuration
 */
$i = 0;

// Change this to use the project and instance that you've created.
$host = '/cloudsql/<app server url>:us-central1:<database name>-app-php';
$type = 'socket';

/*
* First server
*/
$i++;
/* Authentication type */
$cfg['Servers'][$i]['auth_type'] = 'cookie';
/* Server parameters */
$cfg['Servers'][$i]['socket'] = $host;
$cfg['Servers'][$i]['connect_type'] = $type;
$cfg['Servers'][$i]['compress'] = false;
/* Select mysql if your server does not have mysqli */
$cfg['Servers'][$i]['extension'] = 'mysqli';
$cfg['Servers'][$i]['AllowNoPassword'] = true;
/*
 * End of servers configuration
 */

/*
 * Directories for saving/loading files from server
 */
$cfg['UploadDir'] = '';
$cfg['SaveDir'] = '';

$cfg['PmaNoRelation_DisableWarning'] = true;
$cfg['ExecTimeLimit'] = 60;
$cfg['CheckConfigurationPermissions'] = false;
// [END all]

的php.ini:

google_app_engine.enable_functions = "php_uname, getmypid"

最后,register.php这是我的php脚本,位于所有这些文件的当前目录中:

register.php:

<?php

function dbg($data){
    file_put_contents(__DIR__.'/log.txt',$data.PHP_EOL,FILE_APPEND );
}

$conn = mysql_connect(':/cloudsql/<app server url>:us-central1:<database name>',
  'root', // username
  ''      // password
  );
        if (isset($conn) && isset($_POST["Token"])) {
                   $_uv_Token=$_POST["Token"];
                   echo $conn;
                   $q="INSERT INTO users (Token) VALUES ( '$_uv_Token') "
              ." ON DUPLICATE KEY UPDATE Token = '$_uv_Token';";

      $result = mysqli_query($conn,$q) or die(mysqli_error($conn));
    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Inserted successfully created.";

        // echoing JSON response
        echo json_encode($response);
    } else {
        // failed to insert row
        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred.";

        // echoing JSON response
        echo json_encode($response);
    }

    dbg($q); /* where $q is the sql */
    dbg(print_r($result,true)); /* config */

      mysqli_close($conn);
        }
 ?>

我似乎无法找到我的错误。我似乎无法调试或找到任何错误日志,如果我连接到错误的数据库,或者我的REST调用只是因为某种原因被拦截到某处。似乎在客户端,在NotificationInstanceService.java中,注册令牌被发送到服务器,但是服务器实际上从未实际存储id或令牌。我很确定我的应用服务器的所有URL都已正确配置。我尝试$echo所有回复,我得到了但似乎无法找到获取这些$echo语句的位置。任何帮助将非常感激。谢谢!

1 个答案:

答案 0 :(得分:0)

你可以做的一件事就是帮助调试(除了检查php错误日志之外)是编写一个写入文本文件的小函数。

function dbg($data){
    file_put_contents(__DIR__.'/log.txt',$data.PHP_EOL,FILE_APPEND );
}

/* then call it like: */
dbg($q); /* where $q is the sql */
dbg(print_r($cfg,true)); /* config */

然后通过php代码使用它来查看您在各个阶段获得的数据 - 通过ftp下载或使用浏览器浏览到该文件位置。只是一个想法...

<?php

    function dbg($data){
        file_put_contents( __DIR__.'/log.txt', $data.PHP_EOL, FILE_APPEND );
    }

    /* !! assuming `config.inc.php` is available in `register.php` !! */
    dbg( print_r( $cfg, true ) );

    $conn = mysql_connect(':/cloudsql/<app server url>:us-central1:<database name>',
        'root',
        ''
    );

    dbg( 'errors: '.mysql_error( $conn ) );


    if ( $conn && isset( $_POST["Token"] ) ) {
        $_uv_Token=$_POST["Token"];

        dbg('POST-Token: '.$_uv_Token);

        $q="INSERT INTO users (Token) VALUES ( '$_uv_Token') ON DUPLICATE KEY UPDATE Token = '$_uv_Token';";
        dbg('sql: '.$q);


        $result = mysqli_query($conn,$q) or die(mysqli_error($conn));
        dbg('Query succeeded: '.$result);


        if ($result) {

            $response["success"] = 1;
            $response["message"] = "Inserted successfully created.";
            echo json_encode($response);

        } else {
            $response["success"] = 0;
            $response["message"] = "Oops! An error occurred.";
            echo json_encode($response);
        }

        mysql_close( $conn );
    }
?>

config.inc.php中是否包含register.php?我问,因为您在配置文件中定义了各种设置,然后继续,在register.php中再次硬化它们。