Question

我有以下json：

var testjson = {
    "Mytest": [{
        "Testing": {
            "static": {
                "name": "first name"
            },
            "key1": "key1 val",
            "key2": 10

        }
    }, {
        "Testing": {
            "static": {
                "name": "second name"
            },
            "key3": 20,
            "key4": true


        }
    }, {
        "Testing": {
            "static": {
                "name": "third name"
            },
            "key5": "key5 val"

        }
    }]
}

我有以下coffeescript：@ itemNames = (item for item of @mydata).sort (a,b) -> a>b，但我将其更改为以下javascript转换：

var mydata = testjson.Mytest;
var item;

this.itemNames = ((function() {
  var results;
  results = [];
  for (item in mydata) {
    results.push(item);
  }
  return results;
}).call(this)).sort(function(a, b) {
  return a > b;
});
console.log(mydata);//gives: [Object, Object, Object] 
console.log(this.itemNames);//gives: ["0", "1", "2"], but I need it like: ["first name", "second name", "third name"], how can I get it ?

这里我在控制台中输出：["0", "1", "2"]，但我需要它：["first name", "second name", "third name"]，当然如果我在控制台上展开它，它应该显示这些值（如：0: "first name", 1: "second name", 2: "third name"）。创建Fiddle。

请帮助我知道如何获得这些名字并提前致谢。

Answer 1

你可以这样做。你的项目是元素的索引。你需要在索引处获取元素，然后通过name访问属性Testing.static.name。

this.itemNames = ((function() {
  var results;
  results = [];
  for (item in mydata) {
    results.push(mydata[item].Testing.static.name);
  }
  return results;
}).call(this)).sort(function(a, b) {
  return a > b;
});

这是代码。

＆＃13;

var testjson = {
    "Mytest": [{
        "Testing": {
            "static": {
                "name": "first name"
            },
            "key1": "key1 val",
            "key2": 10

        }
    }, {
        "Testing": {
            "static": {
                "name": "second name"
            },
            "key3": 20,
            "key4": true


        }
    }, {
        "Testing": {
            "static": {
                "name": "third name"
            },
            "key5": "key5 val"

        }
    }]
};


var mydata = testjson.Mytest;
var item;

this.itemNames = ((function() {
  var results;
  results = [];
  for (item in mydata) {
    results.push(mydata[item].Testing.static.name);
  }
  return results;
}).call(this)).sort(function(a, b) {
  return a > b;
});

console.log(this.itemNames);

＆＃13;

Answer 2

您可以使用这个简单的解决方案......

var mydata = testJSON.Mytest;
var nameArray = [];
var nameMap= {};
var count =0;
$.each(mydata , function(i , data)
{
    var data1 = data.Testing

    var name = data1.static.name
    nameArray.push(name);
    nameMap[count] = name;
    count ++;
});

console.log(nameArray);
console.log(nameMap);

如何在迭代而不是索引或ID上获取json名称值？

2 个答案: