Question

//此代码可帮助我将图片提交到我的图片文件夹中。但是，由于函数basename，文件保留其原始名称。如何在文件中添加特定名称？喜欢logo.png？

<?php
      if(isset($_POST['submit'])) {
        //PROCESS FORM DATA
        $tmp_file = $_FILES['file_upload']['tmp_name'];
        $target_file = basename($_FILES['file_upload']['name']);
        $upload_dir = "images";

        //Move file
        //False als die niet correct is
        if (move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) {
          $message = "File upload succesfull";
        } else {
          $error = $_FILES['file_upload']['error'];
          $message = $upload_errors[$error];
        }
      }
?>

Html表格：

  <form action="upload_logo.php" enctype="multipart/form-data" method="POST">
    Select .png logo to upload:
    <input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
    <input type="file" name="file_upload" />

    <input type="submit" name="submit" value="Upload" />
  </form>

Answer 1

只需替换此行：

if (move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) {

这一个：

if (move_uploaded_file($tmp_file, $new_file_name)) {

Answer 2

我使用此代码。

date

它始终动态生成文件的唯一名称。它内部有unique id和{{1}}。他们每次都会改变。您无需在此手动更改文件名。

Answer 3

您的代码看起来几乎就在那里 - 只需生成您想要的名称，抓取原始文件扩展名并附加新名称

<?php
      if(isset($_POST['submit'])) {

        $tmp_file = $_FILES['file_upload']['tmp_name'];

        $target_file = 'logo.' . pathinfo( $_FILES['file_upload']['name'], PATHINFO_EXTENSION );

        $upload_dir = "images";


        if (move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) {
            $message = "File upload succesfull";
        } else {
            $error = $_FILES['file_upload']['error'];
            $message = $upload_errors[$error];
        }
      }
?>

如何指定上传的文件名？

3 个答案: