Question

我有gulp.task 'scripts'使用gulp-uglify。然后我还添加了gulp-import，但它没有用。如果我只做uglify它可行。如果我只做import则有效。但如果我同时做两件事都行不通。这是功能：

gulp.task('scripts', function(){
    gulp.src([
            'testgulp/**/*.js', '!testgulp/**/_*.js', '!testgulp/**/*.min.js'
        ])
        .pipe(include()) //if I comment only this line, uglify works
            .on('error', console.log)
        .pipe(uglify()) //if I comment only this line, include works
        .pipe(rename({ suffix: '.min' }))
        .pipe(gulp.dest(function(file) { return file.base; }));

});

然后在终端上我尝试同时做出这个回应：

/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/map-stream/index.js:103
        throw err
        ^
GulpUglifyError: unable to minify JavaScript
    at createError (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/gulp-uglify/lib/create-error.js:6:14)
    at wrapper (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/gulp-uglify/node_modules/lodash/_createHybrid.js:87:15)
    at trycatch (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/gulp-uglify/minifier.js:26:12)
    at DestroyableTransform.minify [as _transform] (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/gulp-uglify/minifier.js:76:19)
    at DestroyableTransform.Transform._read (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/through2/node_modules/readable-stream/lib/_stream_transform.js:159:10)
    at DestroyableTransform.Transform._write (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/through2/node_modules/readable-stream/lib/_stream_transform.js:147:83)
    at doWrite (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/through2/node_modules/readable-stream/lib/_stream_writable.js:313:64)
    at writeOrBuffer (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/through2/node_modules/readable-stream/lib/_stream_writable.js:302:5)
    at DestroyableTransform.Writable.write (/Applications/MAMP/htdocs/git/personal-sandrina-p/_main/v3/node_modules/through2/node_modules/readable-stream/lib/_stream_writable.js:241:11)
    at Stream.ondata (stream.js:31:26)

我正在离开考拉应用程序并且附加/前置功能非常棒，所以我想对Gulp做同样的事情。我尝试了gulp-include和gulp-import，两者都有同样的问题。我做错了什么？谢谢:)）

- 编辑 - 我也试过gulp-sync并在minifyit任务上硬编码超时（），但是没有解决问题......

Answer 1

好的，我想我发现了这个问题。首先，我需要安装gulp-util以更好地找出错误是什么。

gulp.task('scripts', function(){
    gulp.src([
            'assets/scripts/**/*.js',
            '!assets/scripts/**/_*.js',
            '!assets/scripts/**/*.min.js'
        ])
        .pipe(include())
            .on('error', console.log)
        .pipe(uglify().on('error', gutil.log)) //gulp-util
        .pipe(rename({ suffix: '.min' }))
        .pipe(gulp.dest(function(file) { return file.base; }));
});

然后用ES5简写uglify来表示错误。我不得不安装gulp-babel，最后的代码是：

gulp.task('scripts', function(){
    gulp.src([
            'assets/scripts/**/*.js',
            '!assets/scripts/**/_*.js',
            '!assets/scripts/**/*.min.js'
        ])
        .pipe(include())
            .on('error', console.log)
        .pipe(babel({
            presets: ['es2015'], //this fixed a shorthand javascript error
            compact: true
        }))
        .pipe(uglify().on('error', gutil.log)) // gulp-util
        .pipe(rename({ suffix: '.min' }))
});

这解决了我的问题。希望能帮助别人：）

Answer 2

您应该使用泵模块。

DECLARE @testdate DATETIME
SELECT @testdate = '2016-08-23'

SELECT LEFT (CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(@testdate)-1),@testdate),113),6)  
+' to '+LEFT(CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,1,@testdate))),
 DATEADD(mm,1,@testdate)),113),11) AS Date_Value

您可以看到why use pump

Answer 3

将它们作为单独的函数，并在uglify之前包含一个运行：

 gulp.task('include,function({
       // include code here
 });

 gulp.task('uglify',['include'],function({
          // uglify code here
 });

运行uglify函数时，[]之间的include函数将在uglify函数之前运行

使用gulp-uglify gulp-include不起作用

3 个答案: