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我试图在这里创建类似按钮。每当我点击按钮时它会增加1.这里我如何使用foreach()循环从数据库中放入值并在jquery中提供

<script type="text/javascript">
$(document).ready(function(){
  $("#like").click(function() {
    var id='1069347886434951';//this is not artist who likes
    var creation_id= 1;
  $.ajax({
    type: "post",
    url: "<?php echo base_url(); ?>creations/like_creation",
    data:'id='+id + '&creation_id=' +creation_id,//after its split, the split function gives an array
    success: function(response){        
      try{
        if(response=='true'){ 
          var newValue = parseInt($("#like").text()) + 1;            
          $("#"+voteId+'_result').html(newValue);// adds the value to no of like on the client side
        }else{
          alert('Sorry Unable to update..');
        }
      }catch(e) {   
        alert('Exception while request..');
      }   
    },
    error: function(){            
      alert('Error while request..');
    }
   });
    });
  });
  </script>

控制器 控制器将值插入数据库中。如果你使用邮递员输入值，它将使用json upto ajax返回true。我已经在邮递员中尝试过它了。

public function like_creation(){
    //$artist_id=$this->session->userdata('user_id');
    $artist_id=$this->input->post('id');

    //bring creation id from the database when fed using foreach loop
    $creation_id=$this->input->post('creation_id');
    //$up_like1 =0;
    $data1=array(
    'id'=> $this->input->post('id'),//bring it from artist_infors
    'creation_id'=>  $this->input->post('creation_id'),
    'artist_who_likes'=> $artist_id ,

    );

    $query=$this->hbmodel->insert_like($data1);     


    $status= "true";

    echo $status;
}

型号

 public function no_likes($artist_id, $creation_id)
{
    $sql="SELECT count(like_id) as num from likes as l where id='$artist_id'  and creation_id= $creation_id";
    //artist id has to determine whether it is user himself or the one whom       he/she tries to follow
    $query=$this->db->query($sql);
    return $query->result();
}

MySQL qUERY

 CREATE TABLE IF NOT EXISTS `likes` (
`like_id` int(11) NOT NULL AUTO_INCREMENT,
`id` varchar(500) COLLATE utf16_bin DEFAULT NULL,//the artist id whose creation is fed
`creation_id` int(11) DEFAULT NULL,
`artist_who_likes` varchar(500) COLLATE utf16_bin DEFAULT NULL,
PRIMARY KEY (`like_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf16 COLLATE=utf16_bin AUTO_INCREMENT=29 ;

Answer 1

if($.trim(response) === 'true')

问题在于成功的代码。值来自响应但未与字符串

正确比较

如何使用jquery，ajax和codeigniter创建类似按钮

1 个答案: