Question

我正在尝试使用亚马逊的API访问数据。我使用相同的电子邮件和密码创建了产品广告和aws帐户，获得了aws_secret，aws_key和affiliate_associate_key。

然后，我尝试了以下内容：

import bottlenose
aws_key = 'my_aws_key'
aws_secret = 'my_aws_secret' 
aws_associate_tag = 'my_aws_associate_tag'

amazon = bottlenose.Amazon(aws_key, aws_secret, aws_associate_tag)
product = amazon.lookup(ItemId='B00EOE0WKQ')

并且，我得到HTTP 403错误如下（我在urllib2.py文件中添加了一些print语句）：

message from urllib2.py Forbidden
headers from urllib2.py Date: Sun, 21 Aug 2016 05:44:59 GMT
Server: Apache-Coyote/1.1
Vary: Accept-Encoding,User-Agent
Content-Encoding: gzip
Content-Length: 304
Keep-Alive: timeout=2, max=15
Connection: Keep-Alive

code from urllib2.py 403
---------------------------------------------------------------------------
HTTPError                                 Traceback (most recent call last)
<ipython-input-1-973306797553> in <module>()
      5 
      6 amazon = bottlenose.Amazon(aws_key, aws_secret, aws_associate_tag)
----> 7 product = amazon.lookup(ItemId='B00EOE0WKQ')
      8 

/Users/chaitra/anaconda/lib/python2.7/site-packages/bottlenose/api.pyc in __call__(self, **kwargs)
    263         # make the actual API call
    264         response = self._call_api(api_url,
--> 265                                   {'api_url': api_url, 'cache_url': cache_url})
    266 
    267         # decompress the response if need be

/Users/chaitra/anaconda/lib/python2.7/site-packages/bottlenose/api.pyc in _call_api(self, api_url, err_env)
    224                 else:
    225                     # the simple way
--> 226                     return urllib2.urlopen(api_request, timeout=self.Timeout)
    227             except:
    228                 if not self.ErrorHandler:

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in urlopen(url, data, timeout, cafile, capath, cadefault, context)
    152     else:
    153         opener = _opener
--> 154     return opener.open(url, data, timeout)
    155 
    156 def install_opener(opener):

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in open(self, fullurl, data, timeout)
    438         for processor in self.process_response.get(protocol, []):
    439             meth = getattr(processor, meth_name)
--> 440             response = meth(req, response)
    441 
    442         return response

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in http_response(self, request, response)
    551         if not (200 <= code < 300):
    552             response = self.parent.error(
--> 553                 'http', request, response, code, msg, hdrs)
    554 
    555         return response

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in error(self, proto, *args)
    476         if http_err:
    477             args = (dict, 'default', 'http_error_default') + orig_args
--> 478             return self._call_chain(*args)
    479 
    480 # XXX probably also want an abstract factory that knows when it makes

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in _call_chain(self, chain, kind, meth_name, *args)
    410             func = getattr(handler, meth_name)
    411 
--> 412             result = func(*args)
    413             if result is not None:
    414                 return result

/Users/chaitra/anaconda/lib/python2.7/urllib2.py in http_error_default(self, req, fp, code, msg, hdrs)
    559 class HTTPDefaultErrorHandler(BaseHandler):
    560     def http_error_default(self, req, fp, code, msg, hdrs):
--> 561         raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
    562 
    563 class HTTPRedirectHandler(BaseHandler):

HTTPError: HTTP Error 403: Forbidden

尝试过的事情：

我确保所有密钥和associate_tag都来自同一个帐户。
我还同步了我的机器上的时钟（位于中央时区）以同步到加州时区。
我在一个多小时内提出了大约5个请求。

我正在使用Python v 2.7.11并在本地计算机上使用Anaconda的QtConsole运行此代码。

Answer 1

我使用Anaconda云以相同的方式提取数据。我遇到了类似的问题，可能是由于您使用已启用代理并妨碍您访问网络的办公网络运行代码。尝试使用家庭网络并执行代码。

Http 403错误瓶装python（亚马逊API）

1 个答案: