我想得到最后一个值示例
ID NAME SURNAME
1 Mark X
2 Alex Z
我想获得surname等于Z的值,或者插入的最后一个值y具有此代码
DB CLASS
public Cursor getData(){
SQLiteDatabase db = this.getWritableDatabase();
//String selectQuery= "SELECT * FROM "+TABLE_NAME+" ORDER BY column DESC LIMIT 1;";
Cursor cursor = db.rawQuery("SELECT * FROM "+TABLE_NAME,null);
//Cursor cursor = db.rawQuery(selectQuery,null);
return cursor;
}
主要活动
void getDatas(){
Cursor c = helper.getData();
if (c.getCount()==0){
return;
}
StringBuffer buffer = new StringBuffer();
while (c.moveToNext()){
buffer.append(c.getString(2));
}
TEXT=buffer.toString();
}
我得到的例子是= XZ而不是Z
答案 0 :(得分:1)
我想你想要这样的东西:
filtered = filter(check_time, os.listdir(r'my/path'))