以下是密码验证过程的代码,至少有一个小写,一个大写和一个数字。
md-delay
我希望让Python运行,如果import re
password=raw_input('Enter the Password')
x= (re.findall(r'[a-z]',password))
if len(x)==0:
print " at least one 'a-z' requirment not completed"
else:
#(what should i write here to connect this to the next step?)
y=(re.findall(r'[A-Z',password))
if len(y)==0:
print "at least one 'A-Z' requirement not completed"
else:
#(what should i write here?)
z=(re.findall(r'[0-9]',password))
if len(z)==0:
print "at least one '0-9' requirment not completed"
else:
print ' Good password!'
不为0,那么请继续验证x
是否等于0.如果不是,请验证y
不等于0.如果不是,请告诉用户密码是否正常。
答案 0 :(得分:2)
使用if-elif
声明:
import re
password=raw_input('Enter the Password')
if len(re.findall(r'[a-z]',password))==0:
print " at least one 'a-z' requirment not completed"
elif len(re.findall(r'[A-Z]',password)) == 0:
print "at least one 'A-Z' requirement not completed"
elif len(re.findall(r'[0-9]',password)) == 0:
print "at least one '0-9' requirment not completed"
else:
print ' Good password!'
演示:
Enter the Password Axa3
Good password!
Enter the Password aa3
at least one 'A-Z' requirement not completed
Enter the Password A3443E
at least one 'a-z' requirment not completed
答案 1 :(得分:1)
import re
password=raw_input('Enter the Password: ')
problems = []
x = re.findall(r'[a-z]',password)
if not x:
problems.append("at least one 'a-z' requirment not completed")
y = re.findall(r'[A-Z]',password)
if not y:
problems.append("at least one 'A-Z' requirement not completed")
z = re.findall(r'[0-9]',password)
if not z:
problems.append("at least one '0-9' requirment not completed")
if problems:
print ' There were some problems with your password: ' + ', '.join(problems)
else:
print ' Good password!'
答案 2 :(得分:1)
这是一种只使用字符串方法的方法!
p = raw_input('enter password')
if p.islower() or p.isupper() or not any(c.isdigit() for c in p):
print('bad password')
答案 3 :(得分:0)
基本上,你的else子句就是下一个语句,就像这样。你几乎写了它,所有你需要做的就是缩进每个检查。
import re
password=raw_input('Enter the Password')
x= (re.findall(r'[a-z]',password))
if len(x)==0:
print " at least one 'a-z' requirment not completed"
else:
y=(re.findall(r'[A-Z',password))
if len(y)==0:
print "at least one 'A-Z' requirement not completed"
else:
z=(re.findall(r'[0-9]',password))
if len(z)==0:
print "at least one '0-9' requirment not completed"
else:
print ' Good password!'
选项2:
import re
password=raw_input('Enter the Password')
if not (re.findall(r'[a-z]',password)):
print " at least one 'a-z' requirment not completed"
elif not (re.findall(r'[A-Z',password)):
print "at least one 'A-Z' requirement not completed"
elif not (re.findall(r'[0-9]',password)):
print "at least one '0-9' requirment not completed"
else:
print ' Good password!'