使用名称访问Datatemplate

Question

我有TabItem个DataGrid，DataTemplate只有一个DataGrid。

现在我将访问<Window.Resources> <DataTemplate x:Key="ContentTabItem"> <DataGrid Grid.Row="1" Name="_uiDataGrid"/> </DataTemplate> </Window.Resources> <Grid> <TabControl Name="_uiTabControl" SelectionChanged="_uiTabControl_SelectionChanged"> <TabItem Name="_uiTabItembla1" Header="bla1" ContentTemplate="{StaticResource ResourceKey=ContentTabItem}"/> <TabItem Name="_uiTabItembla2" Header="bla2" ContentTemplate="{StaticResource ResourceKey=ContentTabItem}"/> </TabControl> </Grid> ，因为我想更改内容......

_uiDataGrid

我无法使用名称ggplot2

进行访问

Answer 1

尝试这样的方法从内容演示者内容模板中获取数据网格：

var contentPresenter = FindVisualChild<ContentPresenter>(_uiTabControl);
var dt = contentPresenter.ContentTemplate;
var datagrid = DataTemplateName.FindName("_uiDataGrid", contentPresenter) 
as DataGrid;

要查找视觉儿童，请参阅this stackoverflow post.

中提及的FindVisualChildren()和FindVisualChild()功能

public static IEnumerable<T> FindVisualChildren<T>(DependencyObject depObj)
       where T : DependencyObject
{
    if (depObj != null)
    {
        for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
        {
            DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
            if (child != null && child is T)
            {
                yield return (T)child;
            }

            foreach (T childOfChild in FindVisualChildren<T>(child))
            {
                yield return childOfChild;
            }
        }
    }
}

public static childItem FindVisualChild<childItem>(DependencyObject obj)
    where childItem : DependencyObject
{
    foreach (childItem child in FindVisualChildren<childItem>(obj))
    {
        return child;
    }

    return null;
}