Question

我有一个数组moonwalkers并编写了一个函数alphabetizer来按字母顺序对名称进行排序，并先用姓氏对它们进行格式化。

它工作正常，但我如何编写更好的代码？

我使用了这个article by Hubrik并引用Stack Overflow来理解JS中的排序是如何工作的。

我尝试将compare函数重新编写到last name变量中，并弄得一团糟。我怀疑这是因为我仍然试图绕过范围和悬挂。

＆＃13;

var moonWalkers = [
  "Neil Armstrong",
  "Buzz Aldrin",
  "Pete Conrad",
  "Alan Bean",
  "Alan Shepard",
  "Edgar Mitchell",
  "David Scott",
  "James Irwin",
  "John Young",
  "Charles Duke",
  "Eugene Cernan",
  "Harrison Schmitt"
];


var finalNameList = [];

function alphabetizer(names) {
    
    // compare last names
    function compare (a, b) {
        var aName = a.split(" ");
        var bName = b.split(" ");
        var aLastName = aName[aName.length - 1];
        var bLastName = bName[bName.length - 1];
        
        if (aLastName < bLastName) return -1;
        if (aLastName > bLastName) return 1;
        return 0;
    }
    
    names.sort(compare);
    
    // to format names
    for (i = 0; i < names.length; i++) {
        var lastName = names[i].split(" ")[1];
        var firstName = names[i].split(" ")[0];
        var newName = lastName + ", " + firstName;
        
        //  push newName to global var finalNameList
        finalNameList.push(newName);
    }
    
    return finalNameList;
}

console.log(alphabetizer(moonWalkers));

＆＃13;

Answer 1

这种方法并不理想，因为它只是比较姓氏。具有相同姓氏的人不会按名字排序。

请改为尝试：

＆＃13;

var moonWalkers = [
  "Neil Armstrong",
  "Buzz Aldrin",
  "Pete Conrad",
  "Alan Bean",
  "Alan Shepard",
  "Edgar Mitchell",
  "David Scott",
  "James Irwin",
  "John Young",
  "Charles Duke",
  "Eugene Cernan",
  "Harrison Schmitt"
];

function alphabetizer(names) {
    var list = [];

    // format names first
    for (i = 0; i < names.length; i++) {
        var lastName = names[i].split(" ")[1];
        var firstName = names[i].split(" ")[0];
        var newName = lastName + ", " + firstName;
        
        //  push newName to global var finalNameList
        list.push(newName);
    }

    // compare entire name
    return list.sort();
}

console.log(alphabetizer(moonWalkers));

＆＃13;

更新：此版本将在结果中包含中间名称或昵称。如果名称包含类似＆＃34; Jr＆＃34;的后缀，它将无法按预期工作。或＆＃34; Esq＆＃34;。

＆＃13;

var moonWalkers = [
  "Neil Armstrong",
  "Edwin \"Buzz\" Aldrin",
  "Charles \"Pete\" Conrad",
  "Alan Bean",
  "Alan Shepard",
  "Edgar Mitchell",
  "David Scott",
  "James Irwin",
  "John Young",
  "Charles Duke",
  "Eugene Cernan",
  "Harrison \"Jack\" Schmitt"
];

function alphabetizer(names) {
  return names.map(function(name) {
    var full = name.split(" "),
      last = full.pop();
    return last + ", " + full.join(" ");
  }).sort();
}

console.log(alphabetizer(moonWalkers));

＆＃13;

如何在JavaScript中按字母顺序对数组中的姓氏进行排序和格式化

1 个答案: